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2 years ago

Determine e when I = 0.50 A and R = 12 W.

Physics

1 answer:

sammy [17]2 years ago

7 0

Answer:

The correct answer is "24 V".

Explanation:

The given values are:

Current,

I = 0.50 A

Resistance,

R = 12 W

As we know,

⇒ $I = 0.5\times (\frac{E}{2R})$

On substituting the given values, we get

⇒ $0.5= (\frac{E}{4\times 12} )$

⇒ $0.5= (\frac{E}{48} )$

⇒ $E=24 \ V$

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The two blocks in oscillate on a frictionless surface with a period of 1.5 s. The upper block just begins to slip when the ampli

Setler79 [48]

Answer:

0.72

Explanation:

$T$ = Time period of oscillation = 1.5 s

Angular frequency is given as

$w = \frac{2\pi }{T}\\w = \frac{2(3.14) }{1.5}\\w = 4.2 rad/s$

$A$ = Amplitude of oscillation = 40 cm = 0.40 m

$\mu$ = Coefficient of static friction = ?

$a$ = acceleration of the block

$m$ = mass of the block

Maximum acceleration of the block is given as

$a = Aw^{2}$

frictional force is given as

$f = \mu mg$

As per newton's second law

$f = ma \\\\\mu mg = ma \\\mu g = a\\\mu g = Aw^{2}\\\mu (9.8) = (0.40)(4.2)^{2}\\\mu = 0.72$

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2 years ago

WILL MARK BRAINLIEST!

viva [34]

Answer:

True

Explanation:

Newton's first law of motion states that an object at rest will stay at rest unless acted upon by an outside force.

5 0

2 years ago

Read 2 more answers

If your acceleration speed is 15 m/s and you weigh 155 lbs, what is your gravitational force?

sp2606 [1]

Answer:

Gravitational force, F = 1054.65 N

Explanation:

Given,

The accelerating speed, a = 15 m/s²

The mass of your body, m = 155 lbs

= 70.31 Kg

The gravitational force acting in a body is given by the relation

F = m x g

Where g is the acceleration due to gravity of the in which the velocity of the body changes its speed at a constant rate.

∴ a = g

Substituting the values in the above equation

F = 70.31 x 15

= 1054.65 N

Hence, the gravitational force acting on you, F = 1054.65 N

6 0

2 years ago

The 1.5-kg collar C starts from rest at A and slides with negligible friction on the fixed rod in the vertical plane. Determine

arlik [135]

Answer:

Explanation:

check attached image for figure, there is supposed to be a figure for this question containing a distance(height of collar at position A) but i will assume 0.2m or 200mm

Consider the energy equilibrium of the system

$U_{A-B}=\bigtriangleup T\\\\F\cos 30°\times h_A - F\sin30°\times h_A + Wh_A=\frac{1}{2}m(v^2_B-v^2_A)\\\\v_B=\sqrt{\frac{2Fh_A(\cos 30° - \sin30°)+mgh_A}{m+v^2_A}}$

Here, F is the force acting on the collar, $h_A$ is the height of the collar at position A, m is the mass of the collar C, g is the acceleration due to gravity, $v_B$ is the velocity of the collar at position B, and $v_A$ is the velocity of the collar at A

Substitute 14.4N for F, 0.2m for $h_A$ , 1.5kg for m, $9.81m/s^2$ for g and 0 for $v_A$

$v_B=\sqrt{\frac{2(14.4\times 0.2(\cos 30° - \sin30°)+1.5\times 9.81\times 0.2}{1.5+0}}\\\\=\sqrt{\frac{6.618}{1.5}}\\\\=4.412m/s$

Therefore, the velocity at which the collar strikes the end B is 4.412m/s

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2 years ago

A heavy object falls with the acceleration as a light object during free fall. Why?

Lyrx [107]

A heavy object falls with the acceleration as a light object during free fall because of acceleration due to gravity.

Explanation:

A motion can be termed as free fall when the object is completely under the influence of gravity. So in this case, no other force will be acting on the object other than the gravitational force. As the gravity influences the object in free fall, the acceleration attained by any object in free fall is same. And this acceleration is termed as acceleration due to gravity. Since, the gravity gives the acceleration to every object experiencing free fall, then the acceleration should be constant. Thus, a heavy object and a light object will have same acceleration during free fall.

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2 years ago