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3 years ago

A girl goes for a walk. Her motion is recorded on the coordinate plane below. On the plane, each block represents 1 km.

Physics

2 answers:

natali 33 [55]3 years ago

4 0

a) Displacement is a distance between the start and the finish: 4

b) Distance: total length: 2+4+2=8

IgorLugansk [536]3 years ago

3 0

Explanation:

A girl goes for a walk. Her motion is recorded on the coordinate plane below. On the plane, each block represents 1 km.

(a) We need to find the displacement of the girl. The displacement of a particle is equal to the shortest path covered by her. In the given graph, the initial position of the particle is A and finally it comes to point B. So, the displacement of the girl is 4 km.

(b) The distance walked by the girl is equal to the total path covered by her during her entire motion. So, the distance walked by the girl is 2 km + 4 km + 2 km = 8 km.

Hence, this is the required solution.

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A gas expands and does PV work on its surroundings equal to 319 J. At the same time, it absorbs 136 J of heat from the surroundi

LiRa [457]

Answer:

The change in energy of the gas during the process is $-1.83\times 10^{2}$ joules.

Explanation:

We can represent this process by the First Law of Thermodynamics, in which gas does work on its surroundings and absorbs heat from there to describe its change in energy. In other words:

$Q_{in} - W_{out} = \Delta E$

Where:

$Q_{in}$ - Heat absorbed by the gas, measured in joules.

$W_{out}$ - Work done by the gas, measured in joules.

$\Delta E$ - Change in energy, measured in joules.

If we know that $Q_{in} = 1.36\times 10^{2}\,J$ and $W_{out} = 3.19\times 10^{2}\,J$ , the change in energy of the gas is:

$\Delta E = 1.36\times 10^{2}\,J-3.19\times 10^{2}\,J$

$\Delta E = -1.83\times 10^{2}\,J$

The change in energy of the gas during the process is $-1.83\times 10^{2}$ joules.

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3 years ago

Light enters water from air at an angle of 25° with the normal, Θ1. If water has an index of refraction of 1.33, determine Θ2.

vladimir1956 [14]

By Snell's law:

η = sini / sinr. i = 25, η = 1.33

1.33 = sin25° / sinr

sinr = sin25° / 1.33 = 0.4226/1.33 = 0.3177 Use a calculator.

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r ≈ 18.52°

Option A.

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Question 1 of 7What is the change in internal energy if 90 J of thermal energy is added to asystem, and the system does 30 J of

Dmitriy789 [7]

Given:

The thermal energy added to the system is Q = 90 J

The work done by the system on the surroundings is W = 30 J

To find the change in internal energy.

Explanation:

According to the first law of thermodynamics, the change in internal energy can be calculated by the formula

$\Delta U=\text{ Q-W}$

On substituting the values, the change in internal energy will be

$\begin{gathered} \Delta U\text{ =90-30} \\ =60\text{ J} \end{gathered}$

Final Answer: The chage in internal energy is 60 J (option D)

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vladimir2022 [97]

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