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boyakko [2]
3 years ago
14

A girl goes for a walk. Her motion is recorded on the coordinate plane below. On the plane, each block represents 1 km.

Physics
2 answers:
natali 33 [55]3 years ago
4 0

a) Displacement is a distance between the start and the finish: 4

b) Distance: total length: 2+4+2=8

IgorLugansk [536]3 years ago
3 0

Explanation:

A girl goes for a walk. Her motion is recorded on the coordinate plane below. On the plane, each block represents 1 km.

(a) We need to find the displacement of the girl. The displacement of a particle is equal to the shortest path covered by her. In the given graph, the initial position of the particle is A and finally it comes to point B. So, the displacement of the girl is 4 km.

(b) The distance walked by the girl is equal to the total path covered by her during her entire motion. So, the distance walked by the girl is 2 km + 4 km + 2 km = 8 km.

Hence, this is the required solution.

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Assoli18 [71]

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8 0
3 years ago
Arace car accelerates uniformly at 11.3 m/s2. If the race car starts from rest how fast will it
Ganezh [65]

Answer:

75.71 m/s

Explanation:

From equation of motion, acceleration is given by

a=\frac {v-u}{t}where v is the final velocity, u is the initial velocity and t is time taken.

Making v the subject of the above formula

v=at+u

Substituting 6.7 s for time, t and 11.3 for a and taking u as zero since it starts from rest

v=11.3*6.7=75.71 m/s

7 0
3 years ago
An LR circuit contains an ideal 60-V battery, a 42-H inductor having no resistance, a 24-ΩΩ resistor, and a switch S, all in ser
s2008m [1.1K]

Answer:

1.6 s

Explanation:

To find the time in which the potential difference of the inductor reaches 24V you use the following formula:

V_L=V_oe^{-\frac{Rt}{L}}

V_o: initial voltage = 60V

R: resistance = 24-Ω

L: inductance = 42H

V_L: final voltage = 24 V

You first use properties of the logarithms to get time t, next, replace the values of the parameter:

\frac{V_L}{V_o}=e^{-\frac{Rt}{L}}\\\\ln(\frac{V_L}{V_o})=-\frac{Rt}{L}\\\\t=-\frac{L}{R}ln(\frac{V_L}{V_o})\\\\t=-\frac{42H}{24\Omega}ln(\frac{24V}{60V})=1.6s

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3 0
3 years ago
If an otherwise empty pressure cooker is filled with air of room temperature and then placed on a hot stove, what would be the m
Xelga [282]

Answer:

The magnitude of the net force F₁₂₀ on the lid when the air inside the cooker has been heated to 120 °C is \frac{135.9}{A}N

Explanation:

Here we have

Initial temperature of air T₁ = 20 °C = ‪293.15 K

Final temperature of air T₁ = 120 °C = 393.15 K

Initial pressure P₁ = 1 atm = ‪101325 Pa

Final pressure P₂ = Required

Area = A

Therefore we have for the pressure cooker, the volume is constant that is does not change

By Chales law

P₁/T₁ = P₂/T₂

P₂ = T₂×P₁/T₁ = 393.15 K× (‪101325 Pa/‪293.15 K) = ‭135,889.22 Pa

∴ P₂ = 135.88922 KPa = 135.9 kPa

Where Force = \frac{Pressure}{Area} we have

Force = F_{120}=\frac{135.9}{A}N.

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