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boyakko [2]
3 years ago
14

A girl goes for a walk. Her motion is recorded on the coordinate plane below. On the plane, each block represents 1 km.

Physics
2 answers:
natali 33 [55]3 years ago
4 0

a) Displacement is a distance between the start and the finish: 4

b) Distance: total length: 2+4+2=8

IgorLugansk [536]3 years ago
3 0

Explanation:

A girl goes for a walk. Her motion is recorded on the coordinate plane below. On the plane, each block represents 1 km.

(a) We need to find the displacement of the girl. The displacement of a particle is equal to the shortest path covered by her. In the given graph, the initial position of the particle is A and finally it comes to point B. So, the displacement of the girl is 4 km.

(b) The distance walked by the girl is equal to the total path covered by her during her entire motion. So, the distance walked by the girl is 2 km + 4 km + 2 km = 8 km.

Hence, this is the required solution.

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Help please
Anarel [89]

Answer:

1) D, 2) D, 3) B, 4) B, 5) C

Explanation:

You are asked to select the correct answer

1)  The conservation of energy is one of the most important principles of physics that allows solving countless problems in life.

the correct answer is D

2) when a body falls, the gravitational potential energy is transformed into kinetic energy and both are transformed into thermal energy

the correct answer is D

3) When the gravitational potential energy is maximum, the kinetic energy is minimum and when the kinetic energy is maximum, the gravitational energy is minimum.

Correct answer B

4) speed is defined by

         v = x / t

so the correct answer is B in the SI system

5) when we repeat a measurement several times, the random or statistical errors decrease, therefore the confidence of the measurement increases.

The correct answer is C

4 0
2 years ago
What is the pressure drop due to the Bernoulli Effect as water goes into a 3.00-cm-diameter nozzle from a 9.00-cm-diameter fire
Marianna [84]

Answer:

The pressure and maximum height are 1.58\times10^{6}\ N/m^2 and 161.22 m respectively.

Explanation:

Given that,

Diameter = 3.00 cm

Exit diameter = 9.00 cm

Flow = 40.0 L/s²

We need to calculate the pressure

Using Bernoulli effect

P_{1}+\dfrac{1}{2}\rho v_{1}^2+\rho g h_{1}=P_{2}+\dfrac{1}{2}\rho v_{2}^2+\rho g h_{2}

When two point are at same height so ,

P_{1}+\dfrac{1}{2}\rho v_{1}^2=P_{2}+\dfrac{1}{2}\rho v_{2}^2....(I)

Firstly we need to calculate the velocity

Using continuity equation

For input velocity,

Q=A_{1}v_{1}

v_{1}=\dfrac{Q}{A_{1}}

v_{1}=\dfrac{40.0\times10^{-3}}{\pi\times(1.5\times10^{-2})^2}

v_{1}=56.58\ m/s

For output velocity,

v_{2}=\dfrac{40.0\times10^{-3}}{\pi\times(4.5\times10^{-2})^2}

v_{2}=6.28\ m/s

Put the value into the formula

P_{1}-P_{2}=\dfrac{1}{2}\rho(v_{1}^2-v_{2}^2)

\Delta P=\dfrac{1}{2}\times1000\times(56.58^2-6.28^2)

\Delta P=1.58\times10^{6}\ N/m^2

(b). We need to calculate the maximum height

Using formula of height

\Delta P=\rho g h

Put the value into the formula

1.58\times10^{6}=1000\times9.8\times h

h=\dfrac{1.58\times10^{6}}{1000\times9.8}

h=161.22\ m

Hence, The pressure and maximum height are 1.58\times10^{6}\ N/m^2 and 161.22 m respectively.

8 0
3 years ago
Elements in an blank or blank of the periodic table have similar characteristics
mr_godi [17]
Don't know if this is a True/False questions but that is true

6 0
3 years ago
You climb to the top of a tall water tower and drop a water balloon. As it drops, the balloon is experiencing energy changes. Wh
inysia [295]

The balloon’s potential energy was transformed to kinetic energy as it drops.

Before the balloon was drop it possessed potential energy but at the moment the balloon was dropped the potential energy it possessed was transformed into kinetic energy.

<span>Hope this answer will be a good h<span>elp for you.</span></span>

4 0
3 years ago
You are a member of an alpine rescue team and must get a box of supplies, with mass 3.00 kg , up an incline of constant slope an
Sever21 [200]

Answer:

v = 8.45 m/s

Explanation:

given,

mass  = 3 kg

angle = 30.0°

vertical distance = 3.3 m

μ = 0.06

according to conservation of energy

KE(loss) = PE(gain) + Work done (against\ friction)..............(1)

frictional Force

F_f = \mu N

F_f = \mu m g cos \theta

work against friction

W = F d

W = \mu m g cos \theta \times h l sin\theta

W = \dfrac{\mu m g \times h}{tan\theta}

Potential energy

PE = mgh

\dfrac{1}{2}mv^2= \dfrac{\mu mgh}{tan \theta}+ mgh

\dfrac{1}{2}v^2= \dfrac{0.06 \times 9.81 \times 3.3}{tan 30^0}+ 9.8\times 3.3

v = 8.45 m/s

the minimum speed is equal to 8.45 m/s

6 0
3 years ago
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