Answer:
The specific heat for the metal is 0.466 J/g°C.
Explanation:
Given,
Q = 1120 Joules
mass = 12 grams
T₁ = 100°C
T₂ = 300°C
The specific heat for the metal can be calculated by using the formula
Q = (mass) (ΔT) (Cp)
ΔT = T₂ - T₁ = 300°C - 100°C = 200°C
Substituting values,
1120 = (12)(200)(Cp)
Cp = 0.466 J/g°C.
Therefore, specific heat of the metal is 0.466 J/g°C.
The force needed to accelerate a vehicle with a mass of 1000kg at a rate of 5m/s2 would be 5000
Answer:
The correct answer is Option A.
Explanation:
The total resistance used to calculate the total resistance of the two parallel resistor is given by :

Taking reciprocal of the above equation.

We can also write the above equation as :

On simplification of above equation,

or

Hence, proved.