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avanturin [10]
3 years ago
6

Which statement describes an action-reaction pair?

Physics
2 answers:
Ksju [112]3 years ago
8 0

Answer:

c yan alam konayan e good lock

Molodets [167]3 years ago
7 0

Answer:

A

Explanation:

a pex

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Can anyone please tell me the properties of image formed in a spherical mirror?
notsponge [240]

Answer:

The two rays, CY and DM are diverging rays and when extended behind the mirror, they appear to intersect each other at point M'. Therefore, the properties of the images formed here are formed behind the mirror, between the pole and principal focus (f), the images are diminished and are virtual and erect.

Explanation:

<h2>Spherical Mirrors</h2>

  • There are two kinds of spherical mirrors, concave and convex.

  • The focal point (F) of a concave mirror is the point at which a parallel beam of light is "focussed" after reflection in the mirror. ...

  • The focal length (f) and radius of curvature (R) are defined in the diagram at the right.

<h3>hope it helps and thanks for following </h3><h2>please give brainliest </h2>
6 0
3 years ago
Read 2 more answers
Car A with a mass of 725 kilograms is traveling east at an initial velocity of 15 meters/second. It collides head–on with car B,
ikadub [295]

Answer:

p_t_o_t_a_l=250kg\frac{m}{s}

Explanation:

<u>The total momentum of a system is defined by:</u>

(mv)_t_o_t=m_1v_1+m_2v_2+...

Where,

(mv)_t_o_t is the total momentum or it could be expressed also as p_t_o_t_a_l.

m_1 and m_2 represents the masses of the objects interacting in the system.

v_1 and v_2 are the velocities of the objects of the system.

<em>Remember: </em><em>The momentum is a fundamental physical magnitude of vector type.</em>

We have:

m_1=725 kg

v_1=15\frac{m}{s}\\m_2=625 kg

We are going to take the east side as positive, and the west side as negative. Then the velocity of the car B, has to be <u>negative</u>. It goes in a different direction from car A.

v_2=-17\frac{m}{s}

Then the total momentum of the system is:

p_t_o_t_a_l=m_1v_1+m_2v_2\\p_t_o_t_a_l=(725kg)(15\frac{m}{s})+(625kg)(-17\frac{m}{s})\\p_t_o_t_a_l=10875kg\frac{m}{s}-10625kg\frac{m}{s}\\p_t_o_t_a_l=250kg\frac{m}{s}

8 0
4 years ago
The Doppler effect is the change in
anzhelika [568]

Yes indeed, that is a true statement.  Truer words are seldom written, and I could not agree with you more.

In case you are asking a question, I can kind of see how this might be a question if there is a blank after "... the change in ..." that is to be filled with one or more new words.

If that is the situation, then the blank can be filled with "frequency or wavelength" .

8 0
3 years ago
Read 2 more answers
If an object falls from rest and lands 3.2 seconds later, how many<br> meters did it fall
DIA [1.3K]

Answer:

50.2 meters

Explanation:

When an object falls, it goes a distance d in time t according to the formula:

d=\frac{1}{2}*g*t^{2}

d is the distance in meter, g is the acceleration due to gravity with the value of 9.8m/s^{2} , t is the time in seconds

Therefore, d = \frac{1}{2}*9.8*(3.2)^{2}

d= 50.176 ≈ 50.2m

6 0
3 years ago
A star emits electromagnetic radiation which closely resembles the spectrum of a blackbody. The three star system named Albireo
aksik [14]

Answer:

A = 13000K has a maximum at lam = 1,9984 10⁻⁷ m = 199.84 nm , this star is visually separated from the other two by its constant emission spectrum and is not affected by the other two.

we have a fluctuation of the intensity emitted by the stars.   Consequently by this fluctuation the amateur astronomer can conclude that this system is made up of two stars.

Explanation:

The radiation of a black body is characterized by its temperature, with Wien's law of displacement we can find the maximum wavelength emitted by each star.

                  λ T = 2,898 10⁻³

therefore the emission the star of A = 13000K has a maximum at lam = 1,9984 10⁻⁷ m = 199.84 nm

The emission of the premiere is in the ultraviolet light range, as this star is visually separated from the other two by its constant emission spectrum and is not affected by the other two.

The burst with A = 4300K ​​has a bad emission maximum = 6.7395 10⁻⁷ m = 673.95 nm, which corresponds to an emission in the visible in the orange range, giving a blackbody spectrum of this range, but since the emission is formed by two stars, we see that when the two are placed one in front of the other the intensity of the emission must increase significantly and when they are placed next to each other the intensity reaches its minimum, consequently we have a fluctuation of the intensity emitted by the stars.

Consequently by this fluctuation the amateur astronomer can conclude that this system is made up of two stars.

7 0
3 years ago
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