We use Lenz's law:
emf = -(NBA)/t ; N is the number of turns, B is the magnetic field, A is the area
t = 1/f = 1/10
emf = (-100 x 0.05 x 0.1) / 0.1
emf = -5 V
An elliptical galaxy is a type of galaxy having an approximately ellipsoidal shape and a smooth, nearly featureless brightness profile.
Unlike flat spiral galaxies with organization and structure, they are more three-dimensional, without much structure, and their stars are in somewhat random orbits around the center.
Answer: 20.73m/s
Explanation:
The question simply wants us to calculate the speed of the pitch. The speed will be calculated as:
= Distance/Time
where,
Distance = 85 meters
Time = 4.1 seconds
Speed = Distance/Time
Speed = 85/4.1
Speed = 20.73m/s
Therefore, the speed of the pitch is 20.73m/s.
Answer:
a) v₀ = 69.29 m / s
, b) t = 18.84 s
Explanation:
a) For this exercise we will use the projectile launch equations
x = v₀ₓ t
y = y₀ +
t - ½ g t²
Let's fix our reference system on the volcano, so the horizontal distance x = 1 km = 1000 m and the vertical distance y = -900 m, the initial height of the crater is I = 0 m. Let's replace to find the speeds
v_{oy} = v₀ sin θ
v₀ₓ = v₀ cos θ
y = v₀ sin θ (x / v₀ cos θ) - ½ g (x / v₀ cos θ)2
y = x tan θ - ½ g x² / v₀² sec² θ
½ g x² sec² θ / v₀² = x tan θ - y
v₀² = ½ g x² sec² θ / (x tan θ –y)
Let's calculate
v₀² = ½ 9.8 1000² sec² 40 / (1000 tan 40 - (-900))
v₀ = √ (8.35 10⁶ / 1,739 10³)
v₀ = 69.29 m / s
b) Flight time
x = v₀ₓ t
t = x / v₀ cos θ
t = 1000 / 69.29 cos 40
t = 18.84 s