3 years ago

(HVAC) PLEASE HELP neeed helpp

Engineering

1 answer:

meriva3 years ago

3 0

Answer

Sump heater

Explanation

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3 years ago

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In a CS amplifier, the resistance of the signal source Rsig = 100 kQ, amplifier input resistance (which is due to the biasing ne

lisov135 [29]

Answer:

406.140 KHz

Explanation:

Given data:

Rsig = 100 kΩ

Rin = 100kΩ

Cgs = 1 pF,

Cgd = 0.2 pF, and etc.

Determine the expected 3-dB cutoff frequency

first find the CM miller capacitance

CM = ( 1 + gm*ro || RL )( Cgd )

= ( 1 + 5*10^-3 * 25 || 20 ) ( 0.2 )

= ( 11.311 ) pF

now we apply open time constant method to determine the cutoff frequency

Th = 1 / Fh

hence : Fh = 1 / Th = $\frac{1}{(Rsig +Rin) (Cm + Cgs )}$

= $\frac{1}{( 200*10^3 ) ( 12.311 * 10^{-12} )}$ = 406.140 KHz

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3 years ago

An insulated piston–cylinder device initially contains 1 m3 of air at 120 kPa and 17°C. Air is now heated for 15 min by a 200-W

irakobra [83]

Answer:

∆S1 = 0.5166kJ/K

∆S2 = 0.51826kJ/K

Explanation:

Check attachment for solution

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3 years ago

Air is compressed slowly in a piston-cylinder assembly from an initial state where P1 = 1.4 bar, V1= 4.25 m^3, to a final state

lord [1]

Answer:

W=-940.36 KJ

Explanation:

Given that

$P_1=1\ bar,V_1=4.25 {m^3}$

$P_2=6.8\ bar$

Process follows pv=constant

So this is the isothermal process and work in isothermal process given as

$W=P_1V_1\ln \dfrac{P_1}{P_2}$

Now by putting the values (1.4 bar =140 KPa)

$W=P_1V_1\ln \dfrac{P_1}{P_2}$

$W=140\times 4.25 \ln \dfrac{1.4}{6.8}$

W=-940.36 KJ

Negative sign indicates that this is a compression process and work will given to the system.

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4 years ago

Technician A says that weld-on dent removal attachments may be used on a steel panel.

spin [16.1K]

Answer:

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Explanation:

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3 years ago