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kirill [66]
3 years ago
8

True or false for the 4 questions?

Engineering
1 answer:
MariettaO [177]3 years ago
3 0

Answer:

true, false, true, true

Explanation:

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Many BLANK apply trial and error to develop a product. Please Help! I have one hour to finish. 30 points
Julli [10]

Answer:

Entrepreneurs?

Explanation:

8 0
3 years ago
¿Que piensas respecto al hecho de que María y Efraín rara vez se comunican directamente?
AleksandrR [38]

Answer:

Crean un código usando la naturaleza.

8 0
3 years ago
A cylindrical resistor element on a circuit board dissipates 0.6 W of power. The resistor is 1.5 cm long, and has a diameter of
Burka [1]

Answer:

a. 51.84Kj

b. 2808.99 W/m^2

c. 11.75%

Explanation:

Amount of heat this resistor dissipates during a 24-hour period

= amount of power dissipated * time

= 0.6 * 24 = 14.4 Watt hour

(Note 3.6Watt hour = 1Kj )

=14.4*3.6 = 51.84Kj

Heat flux = amount of power dissipated/ surface area

surface area = area of the two circular end  + area of the curve surface

=2*\frac{\pi D^{2} }{4} + \pi DL\\=2*\frac{\pi *(\frac{0.4}{100} )^{2} }{4} + \pi *\frac{0.4}{100} *\frac{1.5}{100}

= 2.136 *10^-4 m^{2}

Heat flux =\frac{0.6}{2.136 * 10^{-4} } = 2808.99 W/m^{2}

fraction of heat dissipated from the top and bottom surface

=\frac{\frac{2*\pi D^{2} }{4} }{\frac{2*\pi D^{2}}{4} + \pi DL } \\\\=\\\frac{\frac{2*\pi *(\frac{0.4}{100} )^{2} }{4} }{\frac{2*\pi *(\frac{0.4}{100}  )^{2} }{4} +\pi *\frac{0.4}{100} *\frac{1.5}{100} } \\\\=\frac{2.51*10^{-5} }{2.136*10^{-4} } \\\\\= 0.1175

=11.75%

8 0
4 years ago
Read 2 more answers
You want a potof water to boil at 105 celcius. How heavy a
ankoles [38]

Answer:

35.7 kg lid we put

Explanation:

given data

temperature = 105 celcius

diameter = 15 cm

Patm = 101 kPa

to find out

How heavy a  lid should you put

solution

we know Psaturated from table for temperature is 105 celcius is

Psat = 120.8 kPa

so

area will be here

area = \frac{\pi }{4} d^2    ..................1

here d is diameter

put the value in equation 1

area = \frac{\pi }{4} 0.15^2

area = 0.01767 m²

so net force is

Fnet = ( Psat - Patm ) × area

Fnet = ( 120.8 - 101 ) × 0.01767

Fnet = 0.3498 KN = 350 N

we know

Fnet = mg

mass = \frac{Fnet}{g}

mass  = \frac{350}{9.8}

mass = 35.7 kg

so 35.7 kg lid we put

3 0
3 years ago
What tool should be used to loosen or tighten brake or fuel lines?
emmainna [20.7K]

The tool you would use are brake line wrenches.

4 0
4 years ago
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