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3 years ago

Solid iron(III) oxide (Fe,O3) reacts with hydrogen gas (H) to form iron and

Chemistry

1 answer:

Kisachek [45]3 years ago

5 0

8. 4 grams of water will be produced.

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How many moles of NaCl will react completely with 18.5 L F2 gas at 300.0 K and 1.00 atm?

meriva

Hello!

Data:

P (pressure) = 1 atm
V (volume) = 18.5 L
T (temperature) = 300 K
n (number of mols) = ? (in mol)
R (Gas constant) = 0.082 (atm*L/mol*K)

Apply the data to the Clapeyron equation (ideal gas equation), see:
$P*V = n*R*T$

$1*18.5 = n*0.082*300$

$18.5 = 24.6n$

$24.6n = 18.5$

$n = \dfrac{18.5}{24.6}$

$\boxed{\boxed{n \approx 0,752\:mol}}\end{array}}\qquad\checkmark$

Note: If the feedback is to be considered, the closest response is 0.751 mol Nacl

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I hope this helps. =)

3 0

4 years ago

Litmus paper is made from water-soluble dyes which are extracted from lichens. This paper is used as an acid-base indicator. Whi

Nutka1998 [239]

The household substances that will turn blue litmus paper red are: A) bleach and D) Vinegar. This is because bleach contains acidic solutions; and vinegar contains a percentage of organic acids for example, acetic acid.

3 0

3 years ago

A weather balloon is inflated to a volume of 2.2 x 10^3 L with 37.4 g of helium. What is the density of helium in grams per lite

Ede4ka [16]

Density = mass/volume
substituting the given values :
We get :
D = 37.4 / 2.2 x 10^3
D = 0.017 grams/liter

8 0

3 years ago

What is the ph of a 0.10 m solution of ethylamine at 25 oc? the pkb of ethylamine at 25 ºc is 3.25. ethylamine is a weak base?

denis-greek [22]

To determine the pH of a weak base, we use the equation:

pH = 14 + 0.5 log Kb

Therefore,

pH = 14 + 0.5 log 3.25
pH = 14.26

A weak base is a base which does not fully dissociates into ions when in solution. The solution would contain cations, anions and the compound itself. Hope this helps.

5 0

4 years ago

An aqueous mixture of phenol and ammonia has initial concentrations of 0.200 M C6H5OH(aq) and 0.120 M NH3(aq). At equilibrium, t

Whitepunk [10]

Answer:

The equilibrium constant, K, for the reaction = 0.23

Explanation:

Given that

initial concentrations of phenol(C₆H₅OH) = 0.2 Molar

& concentration of ammonia = 0.12 Molar

At equilibrium the phenoxide ion concentration (C₆H₅O⁻) = 0.05 Molar

C₆H₅OH(aq) + NH₃(aq) ⇄ C₆H₅O⁻(aq) + NH₄⁺(aq)

Initial conc. 0.2 0.12 0 0

Equilibrium (0.2 - 0.05) (0.12 - 0.05) 0.05 0.05

= 0.15 = 0.07

According to law of mass action

$K_{c} =\frac{[C_{6}H_{5}O^{-} ][NH_{4}^{+} ]}{[C_{6}H_{5}OH ][NH_{3} ]}$

$=\frac{0.05X0.05}{0.15X0.07}$

$= 0.23$

7 0

3 years ago