Use your periodic table and calculator as needed for the following question.

What are 2 factors that affect gravitational attraction?

marshall27 [118]

The size of the object and the distance between the objects.

3 0

2 years ago

Carbon burns in the presence of oxygen to give carbon dioxide. Which chemical equation describes this reaction?

Phoenix [80]

Answer: Option (B) is the correct answer.

Explanation:

It is known that for writing a chemical reaction equation, reactants are written on left hand side whereas products are written on right hand side.

And in between reactants and products a forward arrow is placed pointing towards the products.

Therefore, the reaction for carbon burns in the presence of oxygen to give carbon dioxide will be written as follows.

$Carbon + Oxygen \rightarrow Carbon dioxide$

Here, carbon and oxygen atoms are the reactants whereas carbon dioxide is the product.

6 0

2 years ago

Recall that your hypothesis is that these values are the fraction of atoms that are still radioactive after n half-life cycles.

Savatey [412]

$0.5^{n}$ means 0.5 raise to the power of n. "To the power of" means an action of multiplication of 0.5 to n times.

The different values of n are given in the table. Substituting these values:

For A:

n = 1 (given)

$0.5^{n} = 0.5^{1} = 0.5$

For B:

n = 2 (given)

$0.5^{n} = 0.5^{2} = 0.5\times 0.5 = 0.25$

For C:

n = 3 (given)

$0.5^{n} = 0.5^{3} = 0.5\times 0.5\times 0.5 = 0.125$

For D:

n = 6 (given)

$0.5^{n} = 0.5^{6} = 0.5\times 0.5\times 0.5\times 0.5\times 0.5\times 0.5= 0.015625$

For E:

n = 8 (given)

$0.5^{n} = 0.5^{8} = 0.5\times 0.5\times 0.5\times 0.5\times 0.5\times 0.5\times 0.5\times 0.5= 0.00390625$

Hence, the values are:

A = 0.5

B = 0.25

C = 0.125

D = 0.015625

E = 0.00390625

4 0

2 years ago

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g 304 mL of a 0.36 M potassium hydroxide solution is added to 341 mL of a 0.51 M lithium hydroxide solution. Calculate the pOH o

Liono4ka [1.6K]

Answer:

pOH = 0.36

Explanation:

Both potassium hydroxide and lithium hydroxide solutions are strong bases, so you assume 100% dissociation.

1. Potassium hydroxide solution, KOH

Volume, V = 304 mL = 0.304 liter

Molarity, M = 0.36 M

number of moles, n = M × V = 0.36M × 0.304 liter = 0.10944 mol

1 mole of KOH produces 1 mol of OH⁻ ion, thus the number of moles of OH⁻ is 0.10944

2. LIthium hydroxide, LiOH

Volume, V = 341 mL = 0.341 liter

Molarity, M = 0.51 M

number of moles, n = M × V = 0.341 liter × 0.51 M = 0.17391 mol

1mole of LiOH produces 1 mol of OH⁻ ion, thus the number of moles of OH⁻ is 0.17391

3. Resulting solution

Number of moles of OH⁻ ions = 0.10944 mol + 0.17391 mol = 0.28335 mol

Volume of solution = 0.304 liter + 0.341 liter = 0.645 liter

Molar concentration = 0.28335 mol / 0.645 liter = 0.4393 M

4. pOH

$pOH=-\log [OH^-]=-\log (0.439)=0.36$ ← answer

5 0

2 years ago

Is the following chemical equation balanced? 2Na + 2H2O 2NaOH + H2

Mumz [18]

yes because you have 2 H 2Na 2O on both sides

8 0

2 years ago

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