How many grams of H2O are needed to produce 150 g of Mg(OH)2? (Molar mass: H2O = 18.02 g/mol; Mg(OH)2 = 58.33 g/mol )
1 answer:
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<u>Answer:</u> The amount of oxygen gas consumed by mouse is 0.202 grams.
<u>Explanation:</u>
We are given:
Initial pressure of air = 769.0 torr
Final pressure of air = 717.1 torr
Pressure of oxygen = Pressure decreased = Initial pressure - Final pressure = (769.0 - 717.1) torr = 51.9 torr
To calculate the amount of oxygen gas consumed, we use the equation given by ideal gas which follows:
where,
P = pressure of the gas = 51.9 torr
V = Volume of the gas = 2.20 L
T = Temperature of the gas = 292 K
R = Gas constant =
n = number of moles of oxygen gas = ?
Putting values in above equation, we get:
To calculate the mass from given number of moles, we use the equation:
Moles of oxygen gas = 0.0063 moles
Molar mass of oxygen gas = 32 g/mol
Putting values in above equation, we get:
Hence, the amount of oxygen gas consumed by mouse is 0.202 grams.
Answer:
The temperature difference of the body after 3 hours = 5.16 K
Explanation:
we know that the number of moles of O₂ inhaled are 0.02 mole/min⁻¹
or, 1.2 mole.h⁻¹
The average heat evolved by the oxidation of foodstuffs is then:
⇒ Q avg = = 7.2 kj.h⁻¹.Kg⁻¹
the heat produced after 3 h would be:
= 7.2 kj. h⁻¹.Kg⁻¹ x 3 h
= 21.6 kj. kg⁻¹
= 21.6 x 10³ j kg⁻¹
We know Qp = Cp x ΔT
Assume the heat capacity of the body is 4.18 J g⁻¹K⁻¹
⇒ ΔT =
⇒ ΔT =
⇒ ΔT = 5.16 K