17. What are the minimum, first quartile, median, third quartile, and maximum of the data set? 40, 7, 2, 35, 12, 23, 18, 28
Rzqust [24]
First step! Arrange the numerals {<span>40, 7, 2, 35, 12, 23, 18, 28} in ascending order: {2, 7, 12, 18, 23, 28, 35, 40}
Count these numerals: there are 8 (an even number)
To find the median of this set of numerals, take the middle 2 values {18, 23} and average them: median = (18+23)/2 = 41/2
Now, on the left of 41/2, we have the subset {2, 7 , 12, 18}. The median of this subset is found in the same way as was 41/2 (above):
(7+12)/2 = 19/2 (First quartile)
The median of the right subset {</span>23, 28, 35, 40} is (28+35)/2, or 63/2. This is the 3rd quartile.
The max. is 40 (this is the largest numeral given).
Answer:
14.5 ft or 14 1/2 ft
Step-by-step explanation:
36in= 1 yard
9x36= 324in (I'm guessing this is the length)
324in (length) -150in (width)= 174in
12 in= 1 ft
174/12= 14 ft 6 in
6 inches is half a foot
14.5 ft or 14 1/2 ft
Answer : 19
5^2-2(3)
25-6
19
Answer:
D) 20,800,000
Step-by-step explanation:
Answer: 9/55
P(1st = red and 2nd = blue)
= (3/11) x (6/10)
= 18/110
= 9/55
To find the probability of something happening,
= (number of desired outcomes) / (total number of outcomes)
If you are finding the probability of more than one thing happening at the same time, you multiply the probability of both things happening together