To solve this problem, we must take two important steps. First we will convert all the given units, to international system. Later we will define the torque, which is given as the product between the radius of application of the force and the Force acting on the body. Mathematically the latter is,
Here,
r = Radius
F = Force
Now the units,
Replacing,
Therefore the torque that the muscle produces on the wrist is 
The electric force on the proton is:
F = Eq
F = electric force, E = electric field strength, q = proton charge
The gravitational force on the proton is:
F = mg
F = gravitational force, m = proton mass, g = gravitational acceleration
Since the electric force and gravitational force balance each other out, set their magnitudes equal to each other:
Eq = mg
Given values:
q = 1.60×10⁻¹⁹C, m = 1.67×10⁻²⁷kg, g = 9.81m/s²
Plug in and solve for E:
E(1.60×10⁻¹⁹) = 1.67×10⁻²⁷(9.81)
E = 1.02×10⁻⁷N/C
Answer:
<h3>The answer is 1200 kg</h3>
Explanation:
The mass of an object can be found by using the formula
f is the force
a is the acceleration
From the question we have
We have the final answer as
<h3>1200 kg</h3>
Hope this helps you
Since force is mass*acceleration,
F = 70kg * 9.8 m/s
Answer:
Two Neutral
Explanation:
If; One postive, and one negative they would be attracked. >-<
If; one postive and the other was postive, (or vice versa) they would repel <->
they both have an electrical charge, and force.
Neutral's are Nueatral. they have to opisition or attraction= No electrical force.
