Answer : The partial pressure of is, 12.34 atm
Explanation :
For the given chemical reaction:
The expression of for above reaction follows:
........(1)
The equilibrium reaction is:
Initial x 0
At eqm (x-y) 2y
Putting values in expression 1, we get:
..............(2)
As we are given that, 25.8 % of remains at equilibrium. That means,
..............(3)
Now put equation 3 in 2, we get the value of 'x'.
Now put the value of 'x' in equation 3, we get:
Now we have to calculate the new partial pressure of at equilibrium.
Partial pressure of = (2y) = (2\times 6.17) = 12.34 atm
Hence, the partial pressure of is, 12.34 atm