Answer:
Do you mean Esterification experiment?
Explanation:
Answer is: V<span>an't Hoff factor (i) for this solution is 2,26.
</span>Change in freezing point
from pure solvent to solution: ΔT =i · Kf · m.
<span>Kf - molal freezing-point depression constant for water is 1,86°C/m.
</span>m - molality, moles of solute per kilogram of solvent.
n(K₂SO₄) = 16,8 g ÷ 174,25 g/mol
n(K₂SO₄) = 0,096 mol.
m(K₂SO₄) = 0,096 mol/kg.
ΔT = 0,405°C.
i = 0,405 ÷ (1,86 · 0,096)
i = 2,26.
For the first question it would be a unit obtained from the change in velocity per unit of time or m/s^2.
The vf and vi represent the final and initial velocity of the object and or item.
Knowing the formula for acceleration is simply change in velocity divided by time
Vi = 0
Vf = 27 m/s
t = 10 s
Vf = vi + at
27 = 10a
a = 27/10 or 2.7 m/s^2.
15 I think because of what you ask I’m a college student so yea
