Answer:
The frictional force acting on the bear during the slide is 207.5 N
Explanation:
Given;
mass of beam, m = 25-kg
vertical height, h = 12 m
speed of fall, v = 6 m/s
Change in potential energy of the beam:
ΔP.E = -mgh = - 25 x 9.8 x 12 = -2940 J
Change in kinetic energy of the beam:
Δ K.E = ¹/₂mv² = ¹/₂ x 25 x (6)² = 450 J
Change in thermal energy of the system due to friction:
ΔE = - (ΔP.E + Δ K.E)
ΔE = - (-2940 J + 450 J)
ΔE = 2940 J - 450 J = 2490 J
Frictional force (in N) acting on the bear during the slide:
F x d = Fk x h = ΔE
Where;
Fk is the frictional force
Fk = ΔE/h
Fk = 2490J / 12m
Fk = 207.5 N
Therefore, the frictional force acting on the bear during the slide is 207.5 N
Yes, in broader terms for people who actually study this, this is called biomechanics. Bio refers to the human body and it moving, while the physics part comes in when a ball is thrown for example and you want to know how far it is thrown.
Anything really like velocity? as long as its not mass, gravity, and height
Ep = mgh
Those are the only variables that affect potential energy
Answer:
b- how much work can be done in a given time
Answer:
r = 2.93 m
Explanation:
mass of the person = 64.8 kg
speed v = 3.44 m/s
Force F = 261 N
using formula
the radius of the chamber is given by
r = 2.93 m
so, the radius of a chamber is equal to 2.93 m
