That’s a dumb question, because It depends on the experiment. I would guess “a” or “d” because in most cases running out of time during a lab, or getting impatient, etc can give you a lower yield.
Unless I’m misreading “d”, it just seems like a more in-depth version of “a”. So it wouldn’t hurt to try that one.
<u>Answer:</u> The equilibrium constant for the given reaction is 1.33
<u>Explanation:</u>
We are given:
Equilibrium concentration of ammonia = 2 M
Equilibrium concentration of nitrogen gas = 3 M
Equilibrium concentration of hydrogen gas = 1 M
For the given chemical equation:
The expression of 
for above equation follows:
![K_{eq}=\frac{[NH_3]^2}{[N_2][H_3]^3}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BNH_3%5D%5E2%7D%7B%5BN_2%5D%5BH_3%5D%5E3%7D)
Putting values in above equation, we get:
Hence, the equilibrium constant for the given reaction is 1.33
Answer: melting, freezing, sublimation, deposition, condensation, and vaporization
Explanation: i stuck at this Answer:Sometimes atoms share more than one pair of electrons, for example a double covalent bond can occur, as in the carbon dioxide molecule where carbon shares 2 pairs of electrons with each oxygen atom: O=C=O. (where = represents a double bond). Another kind of covalent bonding is called co-ordinate or dative covalent.
