Answer:
160 Kg
Explanation:
This problem is solved by considering the mass balance. We know the density of water, which we will assume constant , the volume of water originally in the tank and the flows of water entering and leaving the tank.
Let m₀ mass of water initially in the tank
m₁ mass of water entering the tank and
m₂ mass of water exiting the tank
V tank volume
then
m₀ = D x V = 1000 Kg x 0.30 m³ = 300 Kg
m₁ = D Vwater in x time = 1000 Kg/m³ x 5 x 10⁻³ m /min x 20 min = 100 Kg
m₂ = D x Area Hose x Vel exit x time =
= 1000 Kg /m³ x 3.1416 x ( 0.02 m)² x 0.5 m/s x ( 20 min x 60 s/min)
= 240 Kg
mass of water initially + mass water in - mass water out =
(300 + 100 - 240) Kg = 160 Kg
Answer:
B.
Explanation:
bc it goes from having the potential to move to moving sorry if im wrong tho
Answer:
you didnt show a picture, but if it just exposed then it will probably be a physical change
Explanation:
In all forms of chemical bonds,the energy stored is chemical energy