Hurricane or typhoons occur when large areas of the open ocean soak up heat from the sun t or f

Which component is used to change alternating current to direct current

Ad libitum [116K]

A rectifier is used.

3 0

3 years ago

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A very long insulating cylinder of charge of radius 2.50 cm carries a uniform linear density of 15.0 nC/m. (

Pavlova-9 [17]

Answer:

r2 = 2.401557 cm

distance = 0.10 cm

Explanation:

given data

radius = 2.50 cm

density = 15.0 nC/m

voltmeter read = 175

solution

we know here potential difference that is express as

ΔV = $\frac{\lambda }{2\pi \epsilon _o} ln\frac{r2}{r1}$ ...........1

so here

$ln\frac{r2}{r1} = 2\pi \epsilon _o \times \frac{\triangle V}{\lambda }$

as here $\lambda$ is linear charge density

$\frac{r2}{r1} = e^{2\pi \epsilon _o \times \frac{\triangle V}{\lambda }}$

r2 = r1 × $e^{2\pi \epsilon _o \times \frac{\triangle V}{\lambda }}$

r2 = 2.40 × $e^{2\pi 8.85\times 10^{-12} \times \frac{175}{15\times 10^{-6} }}$

r2 = 2.401557 cm

and

here distance above surface will be

distance = r1 - r2

distance = 2.50 - 2.40

distance = 0.10 cm

4 0

3 years ago

Consider a double-slit with a distance between the slits of 0.04 mm and slit width of 0.01 mm. Suppose the screen is a distance

scZoUnD [109]

Answer:

The distance between the places where the intensity is zero due to the double slit effect is 15 mm.

Explanation:

Given that,

Distance between the slits = 0.04 mm

Width = 0.01 mm

Distance between the slits and screen = 1 m

Wavelength = 600 nm

We need to calculate the distance between the places where the intensity is zero due to the double slit effect

For constructive fringe

First minima from center

$x_{1}=\dfrac{\lambda D}{2d}$

Second minima from center

$x_{2}=\dfrac{3\lambda D}{2d}$

The distance between the places where the intensity is zero due to the double slit effect

$\Delta x_{d}=x_{2}-x_{1}$

$\Delta x_{d}=\dfrac{3\lambda D}{2d}-\dfrac{\lambda D}{2d}$

$\Delta x_{d}=\dfrac{\lambda D}{d}$

Put the value into the formula

$\Delta x_{d}=\dfrac{600\times10^{-9}\times1}{0.04\times10^{-3}}$

$\Delta x_{d}=0.015 =15\times10^{-3}\ m$

$\Delta x_{d}=15\ mm$

Hence, The distance between the places where the intensity is zero due to the double slit effect is 15 mm.

8 0

3 years ago

Every substance has a specific value of heat required to change the temperature of 1 gram of the substance by 1 degree Celsius.

zimovet [89]

I believe the correct answer from the choices listed above is option C. The units for the specific heat capacity or C would be J/g °C. It is <span>the heat required to raise the temperature of the unit mass of a given substance by a given amount .</span>

8 0

3 years ago

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8.

svetoff [14.1K]

Answer:

9.5 seconds

Explanation:

You need to make the ending speed into meters per sec.

So it would be 120km/h = 33.33m/s

If the acceleration rate is 3.5m/s, then the final answer would equal to 9.5 seconds

Also btw rounding it up is a good idea too so 10 seconds if you round

8 0

3 years ago

Hurricane or typhoons occur when large areas of the open ocean soak up heat from the sun t or f​

Hurricane or typhoons occur when large areas of the open ocean soak up heat from the sun t or f