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ivann1987 [24]
3 years ago
12

What I is the mode ..?

Mathematics
1 answer:
taurus [48]3 years ago
3 0
I’m sorry i don’t quite understand the question your asking
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Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.
mart [117]

Answer:

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

Step-by-step explanation:

The given expression is  

\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}

We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

Using properties of exponents, we get

\dfrac{3}{4\cdot 3}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{\frac{3}{2}+\frac{1}{2}}}    [\because a^ma^n=a^{m+n}]

\dfrac{1}{4}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{2}}

\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}         [\because a^{-n}=\dfrac{1}{a^n}]

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

5 0
3 years ago
If a stadium pays $11000 for labor and $7000 for parking what would the stadiums parking revenue be if the stadium is hoping par
Alchen [17]

Answer:

$300,000

Step-by-step explanation:

Labor  cost = $11,000

Parking  cost= $7,000

Parking Labor cost = $ 18,000

Parking Revenue = ?

From the question, parking labor cost is 6% of Parking revenue.

6% =   Parking Labor cost/ Parking Revenue------------------------------------ (1)

Further substituting in (1) gives:

6/100  =  18,000/ Parking Revenue

Making Parking Revenue the subject of the formula, we have:

Parking Revenue = (100 x 18,000)/6

                             = $300,000

4 0
3 years ago
Find each measure.<br> m1, m2, m3
lyudmila [28]

Answer:

second option

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

∠ 1 and 33° form a straight angle and are supplementary, thus

∠ 1 = 180° - 33° = 147°

----------------------------------

The third angle in the triangle on the left is

180° - (33 + 47)° = 180° - 80° = 100°, thus

∠ 2 = 180° - 100° = 80°

--------------------------------------

∠ 2 and the angle in the triangle form a straight angle and are supplementary,

angle = 180° - 80° = 100°

The third angle in the triangle on the right is

180° - (100 + 48)° = 180° - 148° = 32°, thus

∠ 3 = 180° - 32° = 148° ( straight angle )

Thus

∠ 1 = 147°, ∠ 2 = 80°, ∠ 3 = 148°

6 0
3 years ago
Use the following figure to answer the question. 1 and 8 are ____ angles.
sergij07 [2.7K]

<1 and <8 are alternate exterior angles

Hope it helps

7 0
3 years ago
Read 2 more answers
The graph shows a reflection.<br><br> True or false: The pre-image and the image are not congruent.
LuckyWell [14K]

Answer:

False

Step-by-step explanation:

That is false

If the pre-image is reflected over any axis, the image will still be congruent to it

8 0
3 years ago
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