Which most likely indicates a chemical change has occurred?

What measurements or observations tells you that a car is accelerating

lutik1710 [3]

You need to observe the car at two different times.

-- The first time:
You write down the car's speed, and the direction it's pointing.

-- The second time:
You write down the car's speed and the direction it's pointing, again.

You take the data back to your lab to analyze it.

-- You compare the first and second speed. If they're different,
then the car had acceleration during the time between the two
observations.

-- You compare the first and second direction. If those are different,
even if the speeds are the same, then the car had acceleration during
the time between the two observations.

(Remember, "acceleration" doesn't mean "speeding up".
It means any change in speed or direction of motion.)

8 0

3 years ago

Read 2 more answers

There are two parallel conductive plates separated by a distance d and zero potential. Calculate the potential and electric fiel

taurus [48]

Answer:

The total electric potential at mid way due to 'q' is $\frac{q}{4\pi\epsilon_{o}d}$

The net Electric field at midway due to 'q' is 0.

Solution:

According to the question, the separation between two parallel plates, plate A and plate B (say) = d

The electric potential at a distance d due to 'Q' is:

$V = \frac{1}{4\pi\epsilon_{o}}.\frac{Q}{d}$

Now, for the Electric potential for the two plates A and B at midway between the plates due to 'q':

For plate A,

$V_{A} = \frac{1}{4\pi\epsilon_{o}}.\frac{q}{\frac{d}{2}}$

Similar is the case with plate B:

$V_{B} = \frac{1}{4\pi\epsilon_{o}}.\frac{q}{\frac{d}{2}}$

Since the electric potential is a scalar quantity, the net or total potential is given as the sum of the potential for the two plates:

$V_{total} = V_{A} + V_{B} = \frac{1}{4\pi\epsilon_{o}}.q(\frac{1}{\frac{d}{2}} + \frac{1}{\frac{d}{2}}$

$V_{total} = \frac{q}{4\pi\epsilon_{o}d}$

Now,

The Electric field due to charge Q at a distance is given by:

$\vec{E} = \frac{1}{4\pi\epsilon_{o}}.\frac{Q}{d^{2}}$

Now, if the charge q is mid way between the field, then distance is $\frac{d}{2}$ .

Electric Field at plate A, $\vec{E_{A}}$ at midway due to charge q:

$\vec{E_{A}} = \frac{1}{4\pi\epsilon_{o}}.\frac{q}{(\frac{d}{2})^{2}}$

Similarly, for plate B:

$\vec{E_{B}} = \frac{1}{4\pi\epsilon_{o}}.\frac{q}{(\frac{d}{2})^{2}}$

Both the fields for plate A and B are due to charge 'q' and as such will be equal in magnitude with direction of fields opposite to each other and hence cancels out making net Electric field zero.

3 0

2 years ago

Which observation would be evidence that heat was transferred by radiation?

oksian1 [2.3K]

I think the answer is D

8 0

2 years ago

Jack and jill are married. this year jack earned $72,000 and jill earned $80,000 and they received $4,000 of interest income fro

MaRussiya [10]

<span>If Jack is filing married-filing-separate he would report $76,000 gross income as head of household.</span>

4 0

2 years ago

Change.

solniwko [45]

Option E, Fiat money includes currency, checking deposits and credit cards .

<u>Explanation: </u>

Fiat money has been the currency issued by the government which is not sponsored by actual resources like gold or silver, but by the country that approved it.

Instead of the price of a product, the valuation of fiat money is extracted from the connection between production and consumption and stability of the authorizing state. Fiat currencies, including that of the U.S. dollar, euro, and other major international currencies seem to be the most common paper currencies.

One risk for fiat money is to print too many of those by regimes that contribute to hyperinflation.

Fiat money is government-supported monetary money and is treated as a legal tender. The capital is provided by physical goods such as valuable metals or instruments including checks and credit cards. The world currencies, backed by gold, were symbolic until 1971.

7 0

2 years ago