all 3 are related to each other through their involvement in protein synthesis and transport.
Ribosomes are the sites of protein synthesis and carry out this work by assembling the amino acids in the appropriate sequence, as dictated by the mRNA (messenger RNA).
These cell organelles are most commonly found embedded in the endoplasmic reticulum. Large scale protein synthesis is possible due to the very large surface area offered by the endoplasmic reticulum to the ribosomes.
The main function of the endoplasmic reticulum is to transport the newly synthesized proteins over to the Golgi apparatus. The primary role of the Golgi apparatus is to modify the proteins and encase them into vesicles. From here they are transported to the various parts of the cell.
this is why it's the answer!
Yes because my great grandfather froze at 60 degrees
Answer:- 0.273 kg
Solution:- A double replacement reaction takes place. The balanced equation is:
We have 0.29 L of 22% m/v aluminum nitrate solution. m/s stands for mass by volume. 22% m/v aluminium nitrate solution means 22 g of it are present in 100 mL solution. With this information, we can calculate the grams of aluminum nitrate present in 0.29 L.
= 63.8 g aluminum nitrate
From balanced equation, there is 1:3 mol ratio between aluminum nitrate and sodium chlorate. We will convert grams of aluminum nitrate to moles and then on multiplying it by mol ratio we get the moles of sodium chlorate that could further be converted to grams.
We need molar masses for the calculations, Molar mass of sodium chlorate is 106.44 gram per mole and molar mass of aluminum nitrate is 212.99 gram per mole.
=
sodium chlorate solution is 35% m/m. This means 35 g of sodium chlorate are present in 100 g solution. From here, we can calculate the mass of the solution that will contain 95.7 g of sodium chlorate and then the grams are converted to kg.
= 0.273 kg
So, 0.273 kg of 35% m/m sodium chlorate solution are required.
Answer:
The alkyl ether was yet to be totally dried off after the student recrystallize it .
The suggestion to the student is to redry the alkyl ether product and then reweigh
Explanation:
Based on the information the likely explanation for the problem that arise is that the alkyl ether was not totally dried after the student recrystallize the product which lead to the increase in mass from 270mg to 280mg gaining extra mass of 10mg (270mg -280mg).
Therefore what would be my suggestion to the student is that they should redry the alkyl ether product again and make sure that the water is totally dried off and then reweigh or weigh the product again for the second time .
Answer: 0.55L
Explanation:
Given that,
Original volume of balloon (V1) = 0.3L
Original temperature of balloon (T1) = 25.0°C
[Convert 25.0°C to Kelvin by adding 273
25.0°C + 273 = 298K]
New volume of balloon (V2) = ?
New temperature of balloon (T2# = 275.0°C
[Convert 25.0°C to Kelvin by adding 273
275.0°C + 273 = 548K]
Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law
V1/T1 = V2/T2
0.3L/298K = V2/548K
To get the value of V2, cross multiply
0.3L x 548K = 298K x V2
164.4L•K = 298K•V2
Divide both sides by 298K
164.4L•K /298K = 298K•V2/298K
0.55L = V2
Thus, the new volume of the balloon would be 0.55 litres