The amount of 1,3-dimethyl urea produced would be 32,458 grams or 32.458 kg while that of carbon dioxide would be 16,214 grams of 16.214 kg
<h3>Stoichiometric problem</h3>
From the equation of the reaction, the mole ratio of methyl isocyanate with the products is 2:1 respectively.
Mole of 42,000 kg of methyl isocyanate = 42000/57 = 736.84 moles
Equivalent mole of 1,3-dimethyl urea = 736.84/2 =368.42 moles
Equivaent mole of carbon dioxide = 736.84/2 =368.42moles
Mass of 368.42 moles 1,3-dimethyl urea = 368.42 x 88.1 = 32,458 grams or 32.458 kg
Mass of 368.42 moles of carbon dioxide = 368.42 x 44.01 = 16,214 grams of 16.214 kg
More on stoichiometric problems can be found here: brainly.com/question/14465605
#SPJ1
Answer:
4.7 atm
Explanation:
From the question given above, the following data were obtained:
Total pressure (P) = 15.3 atm
Pressure of Helium, P(He) = 3.2 atm
Pressure of Oxygen, P(O) = 7.4 atm
Pressure of Argon, P(Ar) =?
The pressure of Argon, P(Ar) in the tank can be obtained as illustrated below:
P = P(He) + P(O) + P(Ar)
15.3 = 3.2 + 7.4 + P(Ar)
15.3 = 10.6 + P(Ar)
Collect like terms
15.3 – 10.6 = P(Ar)
4.7 = P(Ar)
P(Ar) = 4.7 atm
Therefore, the pressure of Argon, P(Ar) in the tank is 4.7 atm
Answer:
electrons
Explanation:
protons and neutrons are found in the nucleus while electrons are outside the nucleus
1) Reaction: 3Mg + N₂ → Mg₃N₂.
m(Mg) = 0,225 g
n(Mg) = 0,225 g ÷ 24,3 g/mol = 0,009 mol.
n(Mg) : n(N₂) = 3 : 1
n₁(N₂) = 0,003 mol.
n₂(N₂) = 0,5331 ÷ 28 = 0,019 mol.
n₃(N₂) = 0,019 mol - 0,003 mol = 0,016, m(N₂) = 0,016mol·28g/mol=0,4467g.
or simpler: m(N₂) = 0,225 g + 0,5331 - 0,3114 g = 0,4467 g.
2) Answer is: 6 <span>of fluorine atoms are combined with one uranium atom.
</span>m(U) = 209 g.
m(F) = 100 g.
n(U) = m(U) ÷ M(U)
n(U) = 209 g ÷ 238 g/mol.
n(U) = 0,878 mol.
n(F) = m(F) ÷ M(F)
n(F) = 5,263 mol
n(U) : n(F) = 0,878 mol : 5,263 mol /:0,878.
n(U) : n(F) = 1 : 6.
n - amount of substance
Answer:
A. Law of constant composition or definite proportion
B. Law of conservation of mass
C. Law of multiple proportion
Explanation:
A. The law of constant composition states that "all pure samples of the same chemical compound contain the same proportion of the elements by mass". Considering the pure same of KCl obtained from different locations, their samples regardless of the procedure used to make them or geography wil be in the same proportion when analysed.
B. Law of conservation of mass states that "mass can neither be created nor destroyed". This law applies to all chemical reactions in which matter is only changed from one form to another. In the bulb, magnessium and oxygen merely combines to magnessium oxide. No loss of matter.
C. Law of multiple proportion states that "when two elements combine to form two or more different compounds, the masses of one of the elements which seperately combine with a fixed mass of the other element are in a simple ratio ".
