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stira [4]
3 years ago
13

1.Which of the following would decrease the rate of a chemical reaction?

Chemistry
2 answers:
timama [110]3 years ago
7 0

Answer:

b

Explanation:

beacuse when u reduce the concentration

Contact [7]3 years ago
4 0

Answer:

d.) add a catalyst

Explanation:

ae per I know this is Ur , but I am not sure so u check it

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A gaseous mixture of o2 and n2 contains 35.8 % nitrogen by mass. what is the partial pressure of oxygen in the mixture if the to
lubasha [3.4K]
The partial pressure is the amount of linguistic compound there is which makes the lagitude of the element 64.663
5 0
3 years ago
2.(04.01 LC)
Mila [183]

Answer:

2KClO3 —> 2KCl + 3O2

The coefficients are 2, 2, 3

Explanation:

From the question given above, we obtained the following equation:

KClO3 —> 2KCl + 3O2

The above equation can be balance as follow:

There are 2 atoms of K on the right side and 1 atom on the left side. It can be balance by putting 2 in front of KClO3 as shown below:

2KClO3 —> 2KCl + 3O2

Now, the equation is balanced.

Thus, the coefficients are 2, 2, 3

8 0
3 years ago
Which statement best explains the difference between polar and nonpolar covalent bonds?(1 point)
miv72 [106K]

Answer:

Answer is 4

Explanation:

Polar covalent bonding is a type of chemical bond where a pair of electrons is unequally shared between two atoms. ... If the electronegativity of two atoms is basically the same, a nonpolar covalent bond will form, and if the electronegativity is slightly different, a polar covalent bond will form.

6 0
3 years ago
Read 2 more answers
Why is it important that there is only a small amount of water in the beaker
natita [175]

Answer:

because too much can neutralise the results

4 0
3 years ago
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How many liters of air must react with 2500 mL of hexane in order for combustion to occur completely. The percentage of oxygen i
bagirrra123 [75]

Answer:

118750 ml

Explanation:

The chemical equation for complete combustion of hexane is given as;

2C6H14 + 19O2 → 12CO2 + 14H2O  

From the equation of the reaction;

2 mol of C6H14 reacts with 19 mol of O2

2 ml of C6H14 reacts with 19 ml of O2

2500 mL of C6H14 would react with x ml of O2

2 = 19

2500 = x

x = 2500 * 19 / 2 = 23750 ml

Since oxygen is 20% of air;

23750 = 20 / 100 * (Volume of air)

Volume of air = 23750 * 100 / 20 = 118750 ml

7 0
3 years ago
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