All categories

3 years ago

The process of burning a fossil fuel to release energy is called

Chemistry

1 answer:

Irina-Kira [14]3 years ago

5 0

Answer:combustion

Explanation:

You might be interested in

What is the law of conservation of energy? a. Energy is created and destroyed. b. Energy is not created but is destroyed. c. Ene

Lady bird [3.3K]

Answer:

Energy is neither created nor destroyed.

Explanation:

The law of conservation of energy states that energy can neither be created nor be destroyed. The total energy of an isolated system remains conserved. It never gets 0. It changes from one form of energy to other but never vanishes.

Hence, the correct option is (d) "Energy is neither created nor destroyed"

8 0

3 years ago

Which subatomic particles are found in the nucleus of an oxygen atom?

Ipatiy [6.2K]

Answer:

the answer is protons and neutrons

Explanation:because

5 0

3 years ago

A mixture of A and B is capable of being ignited only if the mole percent of A is 6 %. A mixture containing 9.0 mole% A in B flo

atroni [7]

Explanation:

As it is given that mixture (contains 9 mol % A and 91% B) and it is flowing at a rate of 800 kg/h.

Hence, calculate the molecular weight of the mixture as follows.

Weight = $0.09 \times 16.04 + 0.91 \times 29$

= 27.8336 g/mol

And, molar flow rate of air and mixture is calculated as follows.

$\frac{800}{27.8336}$

= 28.74 kmol/hr

Now, applying component balance as follows.

$0.09 \times 28.74 + 0 \times F_{B} = 0.06F_{p}$

$F_{p}$ = 43.11 kmol/hr

$F_{A} + F_{B} = F_{p}$

$F_{B}$ = 43.11 - 28.74

= 14.37 kmol/hr

So, mass flow rate of pure (B), is $F_{B}$ = $14.37 \times 29$

= 416.73 kg/hr

According to the product stream, 6 mol% A and 94 mol% B is there.

Molecular weight of product stream = $Mol. weight \times 43.11 kmol/hr$

= $0.06 \times 16.04 + 0.94 \times 29$

= 28.22 g/mol

Mass of product stream = 1216.67 kg/hr

Hence, mole of $O_{2}$ into the product stream is as follows.

$0.21 \times 0.94 \times 43.11$

= $8.5099 kmol/hr \times 329 g/mol$

= 272.31 kg/hr

Therefore, calculate the mass % of $O_{2}$ into the stream as follows.

$\frac{272.31}{1216.67} \times 100$

= 22.38%

Thus, we can conclude that the required flow rate of B is 272.31 kg/hr and the percent by mass of $O_{2}$ in the product gas is 22.38%.

4 0

3 years ago

Can chlorine replace iodine?

Viktor [21]

Answer:

The reactivity of the halogen group (group 17) decreases from top to bottom within the group. Fluorine is the most reactive halogen, while iodine is the least. Since chlorine is above bromine, it is more reactive than bromine and can replace it in a halogen replacement reaction.

Explanation:

4 0

3 years ago

What is N for silicon tetrachloride, SiCl4?

lakkis [162]

It might be 40 total needed electrons

5 0

3 years ago