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kap26 [50]
3 years ago
15

Describe a situation in which an electron will be affected by an external electric field but will not be affected by an external

magnetic field. Is it possible that an electron is affected by an external magnetic field but not by an external electric field?
Physics
1 answer:
irina [24]3 years ago
6 0

Answer:

Explanation:

Situations in which an electron will be affected by an external electric field but will not be affected by an external magnetic field

a ) When an electron is stationary in the electric field and magnetic field , he will be affected by electric field but not by magnetic field. Magnetic field can exert force only on mobile charges.

b ) When the electron is moving parallel to electric field and magnetic field . In this case also electric field will  exert force on electron but magnetic field field will not exert force on electrons . Magnetic field can exert force only on the perpendicular component of the velocity of charged particles.

Situations when electron is affected by an external magnetic field but not by an external electric field

There is no such situation in which electric field will not affect an electron . It will always affect an electron .

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The dog’s speed is
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What is the gravitational force between two masses of 15kg each, when their centers are 0.25m? Could you detect this force with
Lunna [17]
Well I don't know !
Let's work it out.

The gravitational force between two objects is

                     F  =  G  ·  M₁·M₂ / R²     .

'G'    is the 'universal gravitational constant'.  We could look it up. 
'M₁'  is the mass of one object
'M₂'  is the mass of the other object 
'R'    is the distance between their centers. 

It looks complicated, but stay with me.  We can do this !
We know all the numbers, so we can calculate the force.

'G'    is  6.67 x 10⁻¹¹ newton·meter² / kg²   (I looked it up.  You're welcome.)
'M₁'  is  15 kg
'M₂'  is  15 kg 
'R'    is  0.25 meter.

Now it's time to pluggum in.

       F  =  G  ·  M₁·M₂ / R²

           = (6.67 x 10⁻¹¹  newton·meter² / kg²) · (15 kg) · (15 kg)  /  (0.25 m²)

           = (6.67 x 10⁻¹¹  ·  15  ·  15 / 0.0625)  N·m²·kg·kg / kg²·m²

           =      2.4 x 10⁻⁷  Newton  .

That a force equivalent to about  0.00000086  of an ounce.
This is the answer to part-a.

Concerning the answer to part-b ...
Personally, I could not detect this force, no matter what kind of equipment
I had. But I am just a poor schlepper engineer, educated in the last Century,
living out my days on Brainly and getting my kicks from YouTube videos. 
I am not pushing the box to the envelope, or thinking outside the cutting
edge ... whatever.
I am sure there are people ... I can't name them, because they keep a
low profile, they stay under the radar, they don't attract a lot of media
attention, their work is not as newsworthy as the Kardashians, and plus,
they seldom call me or write to me ... but I know in my bones that there
are people who have measured the speed of light to NINE significant figures,
aimed a spacecraft accurately enough to take close-up pix of Pluto ten years
later, and detected gravity waves from massive blobs that merged 13 billion
years ago, and I tell you that YES !  THESE guys could detect and measure
a force of  0.86 micro-ounce if they felt like it !
4 0
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Sound waves are longitudinal waves that can travel through air. Would you expect sound waves to travel faster through a low-dens
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Answer:

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Explanation:

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From the equation, we see that the speed of sound is inversely proportional to the square root of the density: therefore, the lower the density, the faster the sound waves.

So, sound waves will travel faster in a low-density gas.

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Explanation:

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