Continuous. Discrete values are values like 1, 2, 3, 4, etc. - they're values that are <em>distinct</em>, and typically there's some idea of a <em>next </em>and a <em>previous </em>value. When we're counting whole numbers, there's a definitive answer to which number comes after, and which number comes before. With continuous values, there's no real "next" or "last" value.
Motion is measured with <em>continuous </em>values; a train might move 300 yards in 1 minute, but we can look at smaller and smaller chunks of time to keep getting shorter and shorter distances. There is no <em />"next" distance the train moves after those 300 yards - it just doesn't make sense for there to be.
It's also measured <em>quantitatively</em>, not <em>qualitatively</em>. This just means that we can use numerical values to measure it, rather than other descriptors like color, smell, or taste.
Answer:
Heat Transfer
Explanation:
This is called heat transfer. Heat transfer is the process in which energy flows from a matter that is higher in heat to a matter that is cooler, until the two matters reach the same temperature.
Mass is measured in kg
Velocity is measured in ms^-1
Hope this is what you were looking for
The Nazca plate will move under the south american plate. i know its late but it will help others!
Answer:
The velocity of water at the bottom, 
Given:
Height of water in the tank, h = 12.8 m
Gauge pressure of water, 
Solution:
Now,
Atmospheric pressue, 
At the top, the absolute pressure, 
Now, the pressure at the bottom will be equal to the atmopheric pressure, 
The velocity at the top,
, l;et the bottom velocity, be
.
Now, by Bernoulli's eqn:

where

Density of sea water, 


