The equation of the reaction for the formation lithium oxide from lithium and oxygen is given as:

<h3>What is the equation for the formation of Lithium oxide?</h3>
Lithium oxide is a compound formed from the reaction between lithium and oxygen.
The equation for the chemical reaction is given below:

Therefore, the reaction between lithium and oxygen yields lithium oxide.
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Answer : The specific heat of this substance is, 1.13 J/g.K
Explanation :
Molar heat capacity : It is defined as the amount of heat absorbed by one mole of a substance to raise its temperature by one degree Celsius.
As we are given that the chemical formula of compound is, 
First we have to calculate the molar mass of given compound.
Molar mass of
= 
Molar mass of
= 78 g/mol
Now we have to calculate the specific heat of this substance.
Specific heat of this substance = 
Specific heat of this substance = 
Specific heat of this substance = 1.13 J/g.K
Thus, the specific heat of this substance is, 1.13 J/g.K
Species that have the same number of electrons or the same electronic structure.
it exists as atom or ion but not as sodium molecule. So there is no any sodium sodium bonding between two sodium atoms. Sodium combines with other element or group to form compounds of sodium like sodium chloride ,sodium carbonate ,sodium sulphate etc. Sodium has symbol Na and its atomic no. is 11 .
Answer:
Q = -811440 J
Explanation:
Given data:
Mass of oil = 2.76 Kg (2.76× 1000 = 2760 g)
Initial temperature = 191 °C
Final temperature = 23°C
Specific heat capacity of oil = 1.75 J/g.°C
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 23°C - 191 °C
ΔT = -168°C
Q = 2760 g ×1.75 J/g.°C ×-168°C
Q = -811440 J
Negative sign show heat is released.