The first two are always the reactants the products come after so they are last
        
             
        
        
        
The equation for work (W) done by an electric field is:
W = qΔV
where q is the magnitude of the charge and ΔV is the potential difference. The question gives you W and q, so plug n' play to find ΔV:
10 = 2ΔV
ΔV = 5
        
             
        
        
        
Answer:
<em>The velocity with which the student goes down the bottom of glide is 12.48m/s.</em>
Explanation:
The Non conservative force is defined as a force which do not store energy or get he energy dissipate the energy from the system as the system progress with the motion.
 Given are 
    <em>  mass of the student 73 kg</em>
<em>      height of water glide 11.8 m</em>
<em>      work done as -5.5*10³ J</em>
Have to find speed at which the student goes down the glide.
According to<em> Law of Conservation of energy</em>,
            K.E =P.E+Work Done
  mv²/2=mgh +W
Rearranging the above eqn for v
v = √2(gh+W/m)
Substituting values,
 V =  12.48 m/s.
<em>The velocity with which the student goes down the bottom of glide is 12.48m/s.</em>
  
 
        
             
        
        
        
Answer:
<u>Acceleration is 2 m/s² </u>
<u>Distance</u><u> </u><u>is</u><u> </u><u>1</u><u>0</u><u>0</u><u> </u><u>m</u>
Explanation:
From definition of acceleration, Acceleration is the rate of change in velocity.
• Simplifying the definition, or modifying it;

• Let's formulate symbols:

- a is acceleration
- v is final velocity, v = 20 m/s
- u is initial velocity, u = 0 m/s [ at rest ]
- t is time, t = 10 seconds

Distance = ut + ½at²
Distance = (0 × 10) + (½ × 2 × 10²)
Distance = 0 + 10²
Distance = 100 meters