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ikadub [295]
3 years ago
12

WILL MARK BRAINLIEST!

Physics
1 answer:
liq [111]3 years ago
5 0
The answer is B. They can only go through solid NOT liquid

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Which structures allow for the removal of wastes from the developing fetus?
castortr0y [4]

The fetus relies upon its mother as it develops. These are some of the things it needs:

<span>protection against knock and bumps, and temperature changes oxygen for respiration nutrients (food and water) </span>

The developing fetus also needs its waste substances removing.

The fetus is protected by the uterus and the amniotic fluid, a liquid contained in a bag called the amnion.


5 0
4 years ago
As in the video, we apply a charge +Q to the half-shell that carries the electroscope. This time, we also apply a charge –Q to t
Andreyy89

Answer:

Explanation:

When the positively charged half shell is brought in contact with the electroscope, its needle deflects due to charge present on the shell.

When the negatively charged half shell is brought in contact with the positively charged shell , the positive and negative charge present on each shell neutralises each other  .So both the shells lose their charges .The positive half shell also loses all its charges

When we separate the half shells , there will be no deflection  in the electroscope because both the shell have already lost their charges and they have become neutral bodies . So they will not be able to produce any deflection in the electroscope.

4 0
3 years ago
Read 2 more answers
An electrical drill has 100 J of chemical energy. Of the 100 J, 45 J are transformed into kinetic energy and 20 J are transforme
Rainbow [258]
The answer to this question is the thermal energy of the drill is 35 J
4 0
3 years ago
Read 2 more answers
Your physics teacher is giving you a special gift a box of mass 20 kg with a mystery surpise insie .the box is placed on a frict
TiliK225 [7]

Answer:

F = 196.2 N

Explanation:

Use Newtons law

F = m * a

F = 20 kg * 9.81 m/s²

F = 196.2 N

7 0
3 years ago
Read 2 more answers
Calculate the solubility (in m units) of ammonia gas in water at 298 k and a partial pressure of 2.50 bar . the henry's law cons
Eduardwww [97]
Henry's Law (formulated in 1803 by William Henry) states that aa constant temperature, the amount of gas dissolved in a liquid is directly proportional to the partial pressure exerted by that gas on the liquid.
 Mathematically it can be formulated as
 C = H⨯P
 being:
 C: the molar concentration of dissolved gas A,
 P: the partial pressure of it
 H: Henry's constant
 Substituting:
 C = P * H
 C = (2.50 * 0.9869) * 58.0
 C = 143.1
 Answer:
 the solubility (in m units) is
 C = 143.1
8 0
3 years ago
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