It makes the data thet they collect more reliable so if they need the data again, they have already tested it a few times so therefor they know that it is right.
Answer:1.71 m/s
Explanation:
Given
mass of Susan 
Inclination 
Tension 
coefficient of Friction 
Resolving Forces Along x axis

where

since there is no movement in Y direction therefore

and 
Thus 


Work done by applied Force is equal to change to kinetic Energy




Answer:
The rate of heat conduction through the layer of still air is 517.4 W
Explanation:
Given:
Thickness of the still air layer (L) = 1 mm
Area of the still air = 1 m
Temperature of the still air ( T) = 20°C
Thermal conductivity of still air (K) at 20°C = 25.87mW/mK
Rate of heat conduction (Q) = ?
To determine the rate of heat conduction through the still air, we apply the formula below.


Q = 517.4 W
Therefore, the rate of heat conduction through the layer of still air is 517.4 W
Answer: Hello, The opposite of rebel is supporter, adherent.
Explanation: