Answer:
<u>We are given:</u>
v1 = 3.2 L v2 = x L
p1 = 822 torr OR 1.08 atm p2 = 2.33 atm
t1 = t2 = 284 k
<u></u>
<u>From the Ideal gas equation:</u>
PV = nRT
Since the number of moles (n), universal gas constant (R) and Temperature (T) are constant
PV = k (where k is a constant)
it can also be written as:
P1V1 = k --------------------------(1)
Similarly,
P2V2 = k (where k is the same constant as before)----------(2)
<u>Solving for V2:</u>
From (1) and (2):
P1V1 = P2V2
Replacing the variables
1.08 * 3.2 = 2.33 * x
x = (1.08 * 3.2)/2.33
x = 1.5 L (approx)
Therefore, the final volume of the solution will be 1.5L
Mass of K = 39.1g/mole
Mass of H = 1g/mole
Mass of C = 12g/mole
Mass of O = 16g/mole
Mass of KHCO3 = 39.1 + 1 + 12 + 3*16 = 100,1g/mole
100% ------------ 100.1g of KHCO3
x% ----------------- 12g of C
x = 11,99% of C in KHCO3
100% -------------- 100.1 of KHCO3
y% --------------------3*16g of O
y = 47,95% of O in KHCO3
100% ------------- 100.1g of KHCO3
z% ---------------- 1g of H
z = 0,99% of H in KHCO3
11,99% + 47,95% + 0,99% = 60,93% ≈ 61%
<u>answer: C</u>
Non metals can not give electrons to hydrogen in water to be released as H2 gas
It will produce high concentration of hydrogen ions if acid ionises completely in water.
According to Wikipedia it is 1,454′ to tip