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Anit [1.1K]
3 years ago
10

Weather, such as thunderstorms or rain showers, takes place in the _____. A. troposphere B. mesosphere C. stratosphere D. thermo

sphere
Chemistry
2 answers:
cestrela7 [59]3 years ago
8 0
Hello there, the correct answer is:

B.
sasho [114]3 years ago
6 0
Answer is A)<span> troposphere</span>
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Heres a list of Compounds and Molecules
kobusy [5.1K]

Answer:

ibgb ybhy

Explanation:

7 0
2 years ago
When humans burn fuel or cut down trees, they (increase/decrease) levels of carbon dioxide in the atmosphere.
Arturiano [62]
When humans burn fuel/cut down tress, they will increase the level of carbon dioxide within the atmosphere. Tress "inhale" the carbon dioxide within the atmosphere and without them, the excess will still linger. Carbon dioxide is a byproduct of burning fuel thus, it will increase the levels in the atmosphere.
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3 years ago
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Its eeeeeeeeeeeezzzzzzzzzzzzzzzz science
artcher [175]

Answer:

B

Explanation:

Meters squared would be a good unit of measurement for Sanjeev's purposes.

4 0
3 years ago
Aqueous concentrated nitric acid is 69% hno3 by weight and has a density of 1.42 g/ml.
OleMash [197]

Answer: -

15.55 M

35.325 molal

Explanation: -

Let the volume of the solution be 1000 mL.

Density of nitric acid = 1.42 g/ mL

Total Mass of nitric acid Solution = Volume of nitric acid x Density of nitric acid

= 1000 mL x 1.42 g/ mL

= 1420 g.

Percentage of HNO₃ = 69%

Amount of HNO₃ = \frac{69} {100} x 1420 g

= 979.8 g

Molar mass of HNO₃ = 1 x 1 + 14 x 1 + 16 x 3 = 63 g /mol

Number of moles of HNO₃ = \frac{979.8 g}{63 g/ mol}

= 15.55 mol

Molarity is defined as number of moles per 1000 mL

We had taken 1000 mL as volume and found it to contain 15.55 moles.

Molarity of HNO₃ = 15.55 M

Mass of water = Total mass of nitric acid solution - mass of nitric acid

= 1420 - 979.8

= 440.2 g

So we see that 440.2 g of water contains 15.55 moles of HNO₃

Molality is defined as number of moles of HNO₃ present per 1000 g of water.

Molality of HNO₃ = \frac{15.55 x 1000}{440.2}

= 35.325 molal

3 0
3 years ago
Question 044 Which of the following sequences converts 2-methylpropene and sodium acetylide into 3-methylbutanal? 1) HBr; 2) NaC
Minchanka [31]

Answer:

1) HBr; 2) NaCCH; 3) O3; 4) H2O

Explanation:

The first step is formation of alkyl halide followed by reaction with sodium acetylide, to form 3-methylbutene, which is then followed by oxidation reaction with O3& H2O to 3-methylbutanal

8 0
3 years ago
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