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masha68 [24]
2 years ago
12

2 Points

Chemistry
2 answers:
konstantin123 [22]2 years ago
6 0

Answer:

A, a reactant.

11Alexandr11 [23.1K]2 years ago
5 0
I would say A. aswell
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What volume of O2 collected at 22.0 and 728 mmHg would be produce by the decomposition of 8.15 g KClO3?
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Explanation:

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Step 2: The balanced equation

2KClO3(s) → 2KCl(s) + 3O2(g)

Step 3: Calculate moles of KClO3

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Moles KClO3 = 0.0665 moles

Step 4: Calculate moles of O2

For 2 moles of KClO3 we'll have 2 moles of KCl and 3 moles of O2 produced

For 0.0665 moles of KClO3 we have 3/2 * 0.0665 = 0.09975 moles

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p*V = n*R*T

V = (n*R*T)/p

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