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3 years ago

Which of the following statements is not a description of asteroids?

Chemistry

2 answers:

seraphim [82]3 years ago

6 0

Answer: Most of them lie in a belt between Earth and Mars.

Explanation:

Asteroids are small rocky bodies having irregular shape size which orbit sun. Majority of the asteroids are found in a belt between orbits of Mars and Jupiter. Scientists presume that these asteroids are remains of a planet that never formed between Mars and Jupiter due to great gravitational pull of the largest planet of the solar -system - Jupiter.

Thus, the incorrect description of the asteroids is: Most of them lie in a belt between Earth and Mars.

saw5 [17]3 years ago

5 0

Answer:

Most of them lie in a belt between Earth and Mars.

Explanation:

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4 years ago

Note the molecular mass of a copper(I) oxide molecule in the image below. What is the mass of 8.250 moles of Cu2O?

xz_007 [3.2K]

Answer : The mass of copper(I) oxide is, 1180.5 grams.

Explanation : Given,

Moles of copper(I) oxide = 8.250 mol

Molar mass of copper(I) oxide = 143.09 g/mol

Formula used:

$\text{ Mass of copper(I) oxide}=\text{ Moles of copper(I) oxide}\times \text{ Molar mass of copper(I) oxide}$

Now put all the given values in this formula, we get:

$\text{ Mass of copper(I) oxide}=(8.250moles)\times (143.09g/mole)=1180.5g$

Therefore, the mass of copper(I) oxide is, 1180.5 grams.

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3 years ago

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3 years ago

1.42 g H2 is allowed to react with 10.4 g N2 , producing 2.14 g NH3 . Part A What is the theoretical yield in grams for this rea

Bad White [126]

Taking into account the reaction stoichiometry, the theorical yield for the reaction is 8.0467 grams of NH₃.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

3 H₂ + N₂ → 2 NH₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

H₂: 3 moles
N₂: 1 mole
NH₃: 2 moles

The molar mass of the compounds is:

H₂: 2 g/mole
N₂: 28 g/mole
NH₃: 17 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

H₂: 3 moles ×2 g/mole= 6 grams
N₂: 1 mole ×28 g/mole= 28 grams
NH₃: 2 moles ×17 g/mole= 34 grams

<h3>Limiting reagent</h3>

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

<h3>Limiting reagent in this case</h3>

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 28 grams of N₂ reacts with 6 grams of H₂, 10.4 grams of N₂ reacts with how much mass of H₂?

$mass of H_{2} =\frac{10.4 grams of N_{2}x 6 grams of H_{2} }{28 grams of N_{2}}$

<u><em>mass of H₂= 2.2286 grams</em></u>

But 2.2286 grams of H₂ are not available, 1.42 grams are available. Since you have less mass than you need to react with 10.4 grams of N₂, H₂ will be the limiting reagent.

<h3>Definition of theorical yield</h3>

The theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

<h3>Theoretical yield in this case</h3>

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 6 grams of H₂ form 34 grams of NH₃, 1.42 grams of H₂ form how much mass of NH₃?

$mass of NH_{3} =\frac{1.42 grams of H_{2} x 34 grams of NH_{3}}{6grams of H_{2} }$