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romanna [79]
2 years ago
6

Please help me ont this​

Chemistry
2 answers:
34kurt2 years ago
7 0

Answer:

H

Explanation:

This will give it the perfect balance to roll straight and steady.

KATRIN_1 [288]2 years ago
7 0

Answer:

free

Explanation:

points thx

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What is the kinetic energy of 3500 kg bus that is moving at 25 m/s
Bond [772]

Answer:

<h2>1093750 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

v is the velocity

m is the mass

From the question we have

k =  \frac{1}{2}  \times 3500 \times  {25}^{2}  \\  = 1750 \times 625 \\  = 1093750 \:  \:  \:  \:  \:

We have the final answer as

<h3>1,093,750 J</h3>

Hope this helps you

8 0
3 years ago
What is the relationship between temperature and volume?
Lelu [443]

Answer:

Charles's law states that the volume of a given amount of gas is directly proportional to its temperature on the kelvin scale when the pressure is held constant

The volume of a given gas sample is directly proportional to its absolute temperature at constant pressure (Charles's law). The volume of a given amount of gas is inversely proportional to its pressure when temperature is held constant (Boyle's law)

Explanation:

~Hope this helps

6 0
3 years ago
How many grams of C2H6 are needed to react with 54 grams of O2?
Dmitrij [34]

Answer:

Explanation:

in a combustion of ethane 2 moles of ethane react with 7 moles of O2

now no of moles in 54 gram of O2=mass/ molar mass

moles =54/32=1.7 moles

if 7 moles of O2 required 2 moles of ethane then 1.7 mole required=?

7 moles of O2=2 moles of C2H6

1.7 moles of O2=1.7*2/7=0.5 moles of C2H6

0.5 moles of C2H6 contain how much grams=?

mass= moles*molar mass=0.5*30=15

4 0
2 years ago
Which of the following is used to break Water down to its elements:
nydimaria [60]
A i’m guessing!
.........
4 0
2 years ago
A student has a 0.00124 M HCl (aq) solution and she titrates 25.00 mL of this solution against an unknown potassium hydroxide so
malfutka [58]

Answer:

The Molarity of KOH is

7,01.10^{-4}M

Explanation:

The endpoint indicates the volume necessary to neutralize the moles of acid.

In other words, the point at which the moles of both solutions are the same.

M_{(HCl)}V_{HCl}=n\\ \\M_{(KOH)}V_{KOH}=n

we match these equations and find the concentration of KOH

M_{(HCl)}. V_{(HCl)} =M_{(KOH)} .V_{(KOH)}\\ \\M_{(KOH)}=\frac{M_{(HCl)}. V_{(HCl)}}{V_{(KOH)}} \\\\M_{(KOH) =\frac{(25mL)(0,00124m)}{(44,25mL)}\\\\

M_{(KOH)}=7,01.10^{-4}

5 0
3 years ago
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