1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mila [183]
3 years ago
10

There are 200 turns of wire around an electromagnet. The current in the wire is 6 amp. You want to increase the strength of the

magnet to 1.5 times its present strength. What are two changes you can make to achieve your goal? Show all your calculations.
Physics
1 answer:
lutik1710 [3]3 years ago
3 0

Answer:

i. increasing the number of turns of the wire by half, so that it equals 300.

OR

ii. increasing the value of the current by half of its initial value, so that it equals 9 amp.

Explanation:

An electromagnet consists of a coil of wire wound around a conductor which becomes induced with magnetism when current flows through the coil.

The magnetic strength of the electromagnet can be increased to 1.5 of its initial strength either by;

i. increasing the number of turns by half of its initial value

OR

ii. increasing the current by half of its initial value

The magnetic strength of an electromagnet = I × N

where; I is the amount of current and N the number of turns.

Given that: I = 6 A, N = 200, then;

magnetic strength = 6 ×200

                              = 1200 Ampere turns

i. Increasing the number of turns to 300 and I = 6 A, we have;

magnetic strength = 6 × 300

                              = 1800 Ampere turns

OR

ii. increasing the value of current by half of its initial value, so that N = 200 and I = 9 A;

magnetic strength = 9 ×200

                              = 1800 Ampere turns

You might be interested in
The blade of metal cutter is shorter than that scissors of tailors<br><br>​
Naily [24]

Explanation:it is beause they are sharper and also have less surface area and therefore more pressure

8 0
3 years ago
A 48-volt source is required to furnish 192 watts to a parallel circuit consisting of three resistors of equal value. What is th
dem82 [27]

Answer:

36 Ω

Explanation:

Since the 3 resistors are connected in parallel.

The combined resistance of the resistor is

1/Rc = 1/R + 1/R + 1/R ...................... Equation 1

Where Rc = combined resistance of the three resistor, R1 = Resistance of each of the resistor

Rc = R/3 ....................... Equation 2

The formula of power is given as

P = V²/Rc

Rc = V²/P ................ Equation 3

Where V = Voltage, R =  Combined Resistance, P = power.

Given: V = 48 V, 192 W.

Substitute into equation 3

Rc = 48²/192

Rc = 12 Ω

From equation 2

Rc = R/3

R = 3Rc

Where Rc = 12 Ω

R = 3×12

R = 36 Ω

Hence the resistance on each resistor = 36 Ω

4 0
3 years ago
How do you explain this arrangement of fossils? What might have happened?
e-lub [12.9K]

Answer:

The question lacks a photo to fully answer correctly

If the fossil has its neck bent backwards towards its back, that is the common way to which dinosaurs died.

If the fossil is scattered a bit from its other linking fossil pieces, than it is most likely that the dinosaur was a meal to a predator.

Fossils that are in array but are divided clearly at a section suggests that land moved. Possibly earthquake or Pangea took place.

6 0
2 years ago
Which of the following is an example of in-group bias? A. Avery, who loves to go to car shows B. Shelly, who thinks her cheerlea
Setler [38]

Answer:

B because since SHE is in the team she is in group and it is bias because she treats the other teams as competition. Hope this helps!

Explanation:

8 0
2 years ago
A proton traveling along the x-axis enters a region at x = 0 where the x-component of the electric field is given by E = Ao/x1/2
storchak [24]

.Answer:

The value of the work done is \bf{ 5.29 qA_{0}}.

Explanation:

When a charged particle having charge q is moving through an electric field E, the net force (F) on the charge is

F = qE~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(1)

and the work done (W) by the particle is

W = \int\limits^x_0 {F} \, dx ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(2)

Given, E = \dfrac{A_{0}}{x^{1/2}}.

Substitute the value of electric field in equation (1) and then substitute the result in equation (2).

W &=& \int\limits^7_0 {q\dfrac{A_{0}}{x^{1/2}}} \, dx \\&=& qA_{0} \int\limits^7_0 {x^{-1/2}} \, dx \\&=& 2qA_{0}[x^{1/2}]_{0}^{7}\\&=& 5.29 qA_{0}

7 0
3 years ago
Other questions:
  • A heavy boy and a lightweight girl are balanced on a mass-less seesaw. If they both move forward so that they are one-half their
    6·2 answers
  • A cyclist must travel 800 kilometers. How many days will the trip take if the cyclist travels at an average speed of 16 km/h
    10·1 answer
  • Does the moon light originate from the moon only
    11·1 answer
  • Help plzzzzzzzzzzzzzzzz!
    7·1 answer
  • Objects fall at constant velocity
    12·2 answers
  • How big is the universe I get it only God knows because he created all of it meaning everything.That is real.
    7·1 answer
  • A plane electromagnetic wave travels northward. At one instant, its electric field has a magnitude of 3.7 V/m and points eastwar
    10·1 answer
  • Two balloons (m = 0.021 kg) are separated by a distance of d = 16 m. They are released from rest and observed to have an instant
    13·1 answer
  • Can someone pls help me with this it’s due in a couple of minutes pls I would really appreciate it I will make u brainliest.
    9·1 answer
  • An object of mass 2.0 kg is attached to the top of a vertical spring that is anchored to the floor. The unstressed length of the
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!