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Tom [10]
3 years ago
5

Saturated aqueous sodium chloride(d=1.2g/mL) is added to the following mixtures in order to dry the organic layer. Which layer i

s likely to be on the bottom in each case?a) Sodium chloride layer or layer containing a high density organic compound dissolved in methylene chloride(d=1.4g/mL).b) Sodium chloride layer or a layer containing a low density organic compound dissolved in methylene chloride(d=1.1g/mL)
Chemistry
1 answer:
natali 33 [55]3 years ago
7 0

(a) at the bottom - high density organic compound dissolved in methylene chloride

(b) at the bottom - saturated aqueous sodium chloride

Explanation:

Sodium chloride is dissolved in water while the organic compounds are dissolved in methylene chloride. After mixing the two solutions two layers will form because water (polar molecule) will not mix with the methylene chloride (nonpolar molecule).

The layer with higher density will be at the bottom.

(a) saturated aqueous sodium chloride (d = 1.2 g/mL) - upper layer

high density organic compound dissolved in methylene chloride (d = 1.4 g/mL) - bottom layer

(b) saturated aqueous sodium chloride (d = 1.2 g/mL) - bottom layer

low density organic compound dissolved in methylene chloride (d = 1.1 g/mL) - upper layer

Learn more about:

liquids with different densities

brainly.com/question/5396235

brainly.com/question/9490207

#learnwithBrainly

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A galvanic cell whose cell reaction is 2Fe3+(aq) + Zn(s) → 2Fe2+(aq) + Zn2+(aq) has a cell potential of 0.72V. What is the maxim
sesenic [268]

Answer:

138.96kJ is the maximum electrical work

Explanation:

The maximum electrical work that can be obtained from a cell is obtained from the equation:

W = -nFE

<em>Where W is work in Joules,</em>

<em>n are moles of electrons = 2mol e- because half-reaction of Zn is:</em>

Zn(s) → Zn²⁺(aq) + 2e⁻

F is faraday constant = 96500Coulombs/mol

E is cell potential = 0.72V

Replacing:

W = -2mol*96500Coulombs/mol*0.72V

W = - 138960J =

<h3>138.96kJ is the maximum electrical work</h3>

<em />

5 0
2 years ago
The turnover number is defined as the maximum number of substrate molecules that can be converted into product molecules per uni
Nataliya [291]

Answer:

Explanation:

turn over number = R max / [E]t   = K2

From given , R max = 249 * 10 ^ -6 mol. L^-1

T [E]t = 2.23 n mol. L^-1

           =   2.23 * 10^-9 mol. L^-1

Putting values in above equation,

=          111.65 * 10^3           S^-1

Turn over number is maximum no of substrate molecule that can be converted into product molecules for unit time by enzyme molecule.

5 0
3 years ago
while doing an experiment you got stuck and didn't know how to proceed what will you do to continue with the experiment​
stiv31 [10]

Answer:

Look for extra things to do, small details, until you find a big enough one to go off that to continue

Explanation:

n/a

7 0
3 years ago
PLZZZZZ HELP MEEEEEE
Masja [62]

Answer:

0.0745 mole of hydrogen gas

Explanation:

Given parameters:

Number of H₂SO₄ = 0.0745 moles

Number of moles of Li = 1.5107 moles

Unknown:

Number of moles of H₂ produced = ?

Solution:

To solve this problem, we have to work from the known specie to the unknown one.

The known specie in this expression is the sulfuric acid,  H₂SO₄. We can compare its number of moles with that of the unknown using a balanced chemical equation.

   Balanced chemical equation:

                    2Li   +     H₂SO₄   →   Li₂SO₄   +   H₂

 From the balanced equation;

     

Before proceeding, we need to obtain the limiting reagent. This is the reagent whose given proportion is in short supply. It determines the extent of the reaction.

           2 mole of Li reacted with 1 mole of  H₂SO₄

          1.5107 mole of lithium will react with \frac{1.5107}{2}  = 0.7554mole of H₂SO₄

But we were given 0.0745 moles,

This suggests that the limiting reagent is the sulfuric acid because it is in short supply;

   

   since 1 mole of sulfuric acid produced 1 mole of hydrogen gas;

    0.0745 mole of sulfuric acid will produce 0.0745 mole of hydrogen gas

4 0
3 years ago
7. Convert 5.2 cm of magnesium (Mg) ribbon to mm of Mg ribbon.
Effectus [21]
<h3>Answer:</h3>

52 mm

<h3>Explanation:</h3>

We are given;

  • 5.2 cm of magnesium

Required to convert it to cm

We are going to use the appropriate conversion factor;

  • The units used to measure length include;

Kilometer(km)

10

Hectometer (Hm)

10

Decameter (dkm)

10

Meter(m)

10

Decimeter (dm)

10

Centimeter (cm)

10

Millimeter (mm)

Therefore; the appropriate conversion factor is 10mm/cm

Thus;

5.2 cm will be equivalent to;

= 5.2 cm × 10 mm/cm

= 52 mm

Therefore, the length of magnesium ribbon is 52 mm

7 0
3 years ago
Read 2 more answers
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