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Tom [10]
3 years ago
5

Saturated aqueous sodium chloride(d=1.2g/mL) is added to the following mixtures in order to dry the organic layer. Which layer i

s likely to be on the bottom in each case?a) Sodium chloride layer or layer containing a high density organic compound dissolved in methylene chloride(d=1.4g/mL).b) Sodium chloride layer or a layer containing a low density organic compound dissolved in methylene chloride(d=1.1g/mL)
Chemistry
1 answer:
natali 33 [55]3 years ago
7 0

(a) at the bottom - high density organic compound dissolved in methylene chloride

(b) at the bottom - saturated aqueous sodium chloride

Explanation:

Sodium chloride is dissolved in water while the organic compounds are dissolved in methylene chloride. After mixing the two solutions two layers will form because water (polar molecule) will not mix with the methylene chloride (nonpolar molecule).

The layer with higher density will be at the bottom.

(a) saturated aqueous sodium chloride (d = 1.2 g/mL) - upper layer

high density organic compound dissolved in methylene chloride (d = 1.4 g/mL) - bottom layer

(b) saturated aqueous sodium chloride (d = 1.2 g/mL) - bottom layer

low density organic compound dissolved in methylene chloride (d = 1.1 g/mL) - upper layer

Learn more about:

liquids with different densities

brainly.com/question/5396235

brainly.com/question/9490207

#learnwithBrainly

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Answer:

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7 0
3 years ago
A balloon has a pressure of 3.1 atm at a volume of 155 ml. if the temperature is held constant, what is the volume (ml) if the p
GarryVolchara [31]

Answer:

45.8 mL

Explanation:

If all variables are held constant, the new volume can be found using the Boyle's Law equation. The equation looks like this:

P₁V₁ = P₂V₂

In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new volume by plugging the given values into the equation and simplifying.

P₁ = 3.1 atm                        P₂ = 10.5 atm

V₁ = 155 mL                       V₂ = ? mL

P₁V₁ = P₂V₂                                                 <----- Boyle's Law equation

(3.1 atm)(155 mL) = (10.5 atm)V₂                <----- Insert values

480.5 = (10.5 atm)V₂                                  <----- Multiply 3.1 and 155

45.8 = V₂                                                    <----- Divide both sides by 10.5

4 0
2 years ago
How many grams of NaOH are produced from 20.0 grams of Na2CO3?
natita [175]

Answer:

Hope this helps!

Explanation:

Ans: 15.1 grams

Given reaction:

Na2CO3 + Ca(OH)2 → 2NaOH + CaCO3

Mass of Na2CO3 = 20.0 g

Molar mass of Na2CO3 = 105.985 g/mol

# moles of Na2CO3 = 20/105.985 = 0.1887 moles

Based on the reaction stoichiometry: 1 mole of Na2CO3 produces 2 moles of NaOH

# moles of NaOH produced = 0.1887*2 = 0.3774 moles

Molar mass of NaOH = 22.989 + 15.999 + 1.008 = 39.996 g/mol

Mass of NaOH produced = 0.3774*39.996 = 15.09 grams

4 0
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Answer:

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2 years ago
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