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melisa1 [442]
3 years ago
12

Suppose you are a city engineer with the job of exploring the use of more renewable energy in your city or town. Prepare a pamph

let or powerpoint presentation to tell citizens of your city about hydropower, solar power, wind power, and geothermal power and the potential for each one in your city. Your pamphlet or multimedia presentation should include: a definition of hydropower, solar power, wind power, and geothermal power a discussion of the advantages and disadvantages of each a discussion of which one(s) your city should use the most and why how use of renewable energy will impact your city pictures and/or charts and tables to strengthen your argument
Chemistry
1 answer:
Rus_ich [418]3 years ago
7 0

Explanation:

ymo-djiq-rak brjfjfj jsjsjd0

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How many moles of elemental oxygen gas (o2) must react with elemental chlorine (cl2) to produce 60.7 moles of dichlorine heptoxi
Dafna11 [192]
The balanced chemical reaction that would occur here would be:
7O2 + 2 Cl2 --> 2 Cl2O7 
To determine the moles of oxygen that is needed in the system, we use the given amount of the product that is needed to be produced. Then, we use the relation from the balanced reaction to relate the product and one of the reactants. We do as follows:

moles Cl2O7 = 60.7 mol

moles O2 = 60.7 mol Cl2O7 ( 7 mol O2 / 2 mol Cl2O7 )
moles O2 = 212.45 mol O2

Therefore, about 213 moles of oxygen gas is needed in order to producr 60.7 moles of dichlorine heptoxide.
4 0
4 years ago
The ionic radius of S2- ion is larger than that of Cl- ion. Why?
Tresset [83]

Answer: A sulfur ion has more electron shells than a chlorine ion.

5 0
2 years ago
How much work must be done on a 5-kg snowboard to increase its speed from 2 m/s to 4 m/s?
Alekssandra [29.7K]

Answer:

Option C = 30 j

Explanation:

Given data:

mass of snowboard = 5 Kg

Initial speed = 2 m/s

final speed = 4 m/s

work done = ΔE= ?

ΔE= change in kinetic energy

Solution:

Formula:

K.E (initial) = 1/2 × mv²

K.E (initial)  = 1/2 × 5 Kg . (2m/s)²

K.E (initial) = 1/2 × 20 Kg.m²/s²

K.E (initial) = 10 Kg.m²/s² or 10 J      

   Kg.m²/s² = J

K.E (finial) = 1/2 × mv²

K.E (finial) = 1/2 ×  5 Kg . (4m/s)²

K.E (finial) = 1/2 ×  5 Kg . 16 m²/s²

K.E (finial) = 1/2 × 80 Kg.m²/s²

K.E (finial) = 40 Kg.m²/s²  or 40 J

work done =  ΔE = K.E (finial) - K.E (initial)

work done =  ΔE = 40 J - 10 J

work done =  ΔE = 30 J

6 0
3 years ago
Which of the following most likely requires intermolecular forces?
Shtirlitz [24]

Answer: The intermolecular forces increase with increasing polarization of bonds. Boiling point increases with molecular weight, and with surface area. The three major types of intermolecular interactions are dipole–dipole interactions, London dispersion forces (these two are often referred to collectively as van der Waals forces), and hydrogen bonds. Intermolecular forces are much weaker than the intramolecular forces of attraction but are important because they determine the physical properties of molecules like their boiling point, melting point, density, and enthalpies of fusion and vaporization.In order from strongest to weakest, the intermolecular forces given in the answer choices are: ion-dipole, hydrogen bonding, dipole-dipole, and Van der Waals forces. Ionic bonding is stronger than any of the given intermolecular forces, but is itself NOT an intermolecular force.

Hope this helps.. Stay safe and have a Merry Christmas!!!!!!!!!! :D

8 0
3 years ago
Read 2 more answers
The equilibrium constant of a reaction: A) is not related to the change in free energy of the reaction. B) is the same as the ma
Taya2010 [7]

Answer:) is related to the change in free energy of the reaction--d

Explanation:

For any reaction that is taking place at any moment the change in Gibbs Free Energy is related to the reaction quotient as

 ΔG=ΔG⁰+RTlnQ  

where R-Universal Gas Constant, T- Temperature in Kelvin, Q is the reaction quotient

Now when the system is in equilibrum,    ΔG⁰ which is the standard Gibb's Free Energy,is then  defined as

ΔG⁰=−RTlnK ,

where K is the equilibrium constant. because  ΔG becomes 0 and reaction quotient Q = K

The equilibrum constant   is related to the change in free energy of the reaction.

because when  ΔG is negative, the value of K is high which leads to a spontaneous. reaction

when   ΔG is positive, the value of K is low, which leads to a spontaneous. reaction in the opposite direction.

5 0
4 years ago
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