It should include a digital rectal examination (DRE).
The lower rectum, pelvis, and lower belly are all examined during a digital rectal exam (DRE). Your doctor can use this test to screen for cancer and other health issues, such as male prostate cancer. an unusual lump in the rectum or anus.
Consistently having pencil-shaped feces is a sign of stenosis brought on by a tumor or scarring. DRE should be used to check for masses. To determine whether you could have a prostate issue or prostate cancer, a digital rectal examination (or exam) is performed. Your doctor or nurse will feel your prostate through the back passage's wall (rectum).
Here is another question with an answer similar to this about digital rectal examination (DRE): brainly.com/question/14818668
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Answer:
The muscles of the intestinal wall contract slowly and involuntarily.
The answer is C. A psyc hospital or nursing home
Blood PC02 may be measured by using direct spectrophotometer
Explanation:
Blood gas analysis or arterial blood gas (ABG) test is done to determine blood pH and the amount of oxygen and carbon dioxide dissolved in arterial blood.
Blood PCO2 is the partial pressure of carbon dioxide dissolved in the arterial blood.
ABG or oximetry test is done by using direct spectrophotometry in a spectrophotometer and gas analysis is done by calorimetric methods. Spectrophotmetry is highly used in Medicine to perform quantitative analysis of blood and its composition. The spectrophotometer measures the light intensity or wavelengths absorbed by the sample solution.
Blood PCO2 reflects the degree of exchange gases in and out of the lungs. An increase in PCO2 levels indicates respiratory illnesses like obstructive lung diseases or pulmonary edema; while a decrease indicates conditions like hypoxia, pulmonary embolism, hyperventilation etc.
Answer:
87 mg
Explanation:
To find the dose of acetaminophen for a 3-year-old child with the body surface area of 0.30 m², we use the formula given below
Child dose = child surface area/1.73 × adult dose
Given that the child surface area = 0.30 m² and the adult dose = 500 mg,
Child dose = child surface area/1.73 × adult dose
Substituting the values of the variables into the equation, we have
Child dose = child surface area/1.73 × adult dose
Child dose = 0.30 m²/1.73 × 500 mg
Child dose = 0.1734 × 500 mg
Child dose = 86.71 mg
Child dose = 87 mg to the nearest whole number
