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Oksana_A [137]
3 years ago
11

3.3 Quiz: z-Scores

Mathematics
1 answer:
Sindrei [870]3 years ago
4 0
A. True
It would be true
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A square has 4 right angels and 4 sides with equal angels ;)
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Find the volume of a cylinder with radius 4 m. And height 3 m.
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If g (x) = 1/x then [g (x+h) - g (x)] /h
lys-0071 [83]

Answer:

\dfrac{-1}{x(x+h)}, h\ne 0

Step-by-step explanation:

If g(x) = \dfrac{1}{x}, then g(x+h) = \dfrac{1}{x+h}. It follows that

  \begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}

Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.

  \begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\\&=\frac{1}{h} \left(\frac{x}{x(x+h)} - \frac{x+h}{x(x+h)} \right) \\ &=\frac{1}{h} \left(\frac{x-(x+h)}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{x-x-h}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{-h}{x(x+h)}\right) \end{aligned}

Now we can cancel the h in the numerator and denominator under the assumption that h is not 0.

  = \dfrac{-1}{x(x+h)}, h\ne 0

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3 years ago
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olga_2 [115]

There's no attachment.

5 0
2 years ago
Factor the following<br> polynomial:<br> X^3 + 125
ra1l [238]
X^3 + 5^3
(x+5)x(x^2-X x 5+5^2)

(x+5)x(x^2 -5x+5^2)

(x+5)x(x^2 -5x+25)

(x+5) x (x^2 -5x+25)

6 0
2 years ago
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