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LenKa [72]
3 years ago
12

How are amplitude, intensity, and loudness related?

Physics
1 answer:
Anna11 [10]3 years ago
4 0

Answer:

Amplitude is a measure of the size of sound waves. It depends on the amount of energy that started the waves. Greater amplitude waves have more energy and greater intensity, so they sound louder. The same amount of energy is spread over a greater area, so the intensity and loudness of the sound is less.

Explanation:

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The main difference between a chest and a bounce pass is what?
snow_lady [41]

Answer: The main difference between the three is the mode of transmission. The chest pass is straight through the air towards your teammate. While the bounce pass is directed toward the ground and then at your teammate. Finally, the overhead pass is projected high in the air to avoid defenders.

Explanation:

4 0
3 years ago
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What determines how long it takes for the capacitor to charge?
myrzilka [38]

The time constant determines how long it takes for the capacitor to charge.

To find the answer, we have to know more about the time constant of the capacitor.

<h3>What is time constant?</h3>
  • The time it takes for a capacitor to discharge 36.8% of its charge in a discharging circuit or charge up to 63.2% of its maximum capacity in a charging circuit, given that it has no initial charge, is the time constant of a resistor-capacitor series combination.
  • The circuit's reaction to a step-up (or constant) voltage input is likewise determined by the time constant.
  • As a result, the time constant determines the circuit's cutoff frequency.

Thus, we can conclude that, the time constant determines how long it takes for the capacitor to charge.

Learn more about the time constant here:

brainly.com/question/17050299

#SPJ4

6 0
2 years ago
A football player runs 20 meters North of a football field, and then 15 meters East. The total motion lasted 15 seconds. What wa
vlada-n [284]
Given:
1st run: 20 meters North
2nd run: 15 meters East
time: 15 seconds

Average speed = total distance covered / total time taken
Ave. Speed = (20m + 15m) / 15s
Ave. Speed = 35m / 15s
Ave. Speed = 2 1/3  meters per second
4 0
3 years ago
Mấy bạn việt nam giúp mình với. cần gấp quá
Basile [38]
Saying english so we can help u
6 0
3 years ago
What force must the deltoid muscle provide to keep the arm in this position?
ruslelena [56]

Answer:

Deltoid Force, F_{d} = \frac {r_{a}mgsin\alpha_{a}}{r_{d}sin\alpha_{d}}

Additional Information:

Some numerical information are missing from the question. However, I will derive the formula to calculate the force of the deltoid muscle. All you need to do is insert the necessary information and calculate.  

Explanation:

The deltoid muscle is the one keeping the hand arm in position. We have two torques that apply to the rotating of the arm.

1. The torque about the point in the shoulder for the deltoid muscle, T_{Deltoid}

2. The torque of the arm, T_{arm}  

Assuming the arm is just being stretched and there is no rotation going on,

                        T_{Deltoid} = 0

                       T_{arm} = 0

       ⇒           T_{Deltoid} = T_{arm}

                  r_{d}F_{d}sin\alpha_{d} = r_{a}F_{a}sin\alpha_{a}

Where,

r_{d} is radius of the deltoid

F_{d} is the force of the deltiod

\alpha_{d} is the angle of the deltiod

r_{a} is the radius of the arm

F_{a} is the force of the arm , F_{a} = mg  which is the mass of the arm and acceleration due to gravity

\alpha_{a} is the angle of the arm

The force of the deltoid muscle is,

                                 F_{d} = \frac {r_{a}F_{a}sin\alpha_{a}}{r_{d}sin\alpha_{d}}

but F_{a} = mg ,

                ∴            F_{d} = \frac {r_{a}mgsin\alpha_{a}}{r_{d}sin\alpha_{d}}

7 0
3 years ago
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