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Paha777 [63]
2 years ago
12

To give an idea of sensitivity of the platypus's electric sense, how far from a 80nC n C point charge does the field have this m

agnitude
Physics
1 answer:
SVETLANKA909090 [29]2 years ago
5 0

The question is incomplete. The complete question is :

A platypus foraging for prey can detect an electric field as small as 0.002 N/C.

-To give an idea of sensitivity of the platypus's electric sense, how far from a +80nC point charge does the field have this magnitude?

Solution :

Given electric field,  E = 0.002 N/C

Charge, Q = + 80 nC

$\therefore E = \frac{kQ}{R^2} $

or $R^2=\frac{kQ}{E}$

    $R^2=\frac{9\times 10^9 \times 80 \times 10^{-9}}{0.002}$

   R = 600 m

This is the distance of the charge from the point of observations.

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Answer:

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Explanation:

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Clara rushes 30m to a truck then turns and walks back. Total travel is 120s what is her average velocity?
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Taking into account the definition of velocity, Clara's average velocity is 0.5 m/s.

<h3>Definition of velocity</h3>

Velocity is a physical magnitude that relates the displacement of an object, the time it takes to make this change in position and direction. So it is considered a vector magnitude.

In other words, the velocity can be defined as the amount of space traveled per unit of time with which a body moves, considering the direction, and can be calculated using the expression:

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<h3>Average velocity of Clara</h3>

Clara rushes 30 m to a truck then turns and walks back. Total travel is 120s. Then, you know:

  • distance traveled= 30m rushing + 30m walking back= 60 m
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Replacing in the definition of velocity:

velocity= 60 m÷ 120 s

Solving:

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Finally, Clara's average velocity is 0.5 m/s.

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