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inessss [21]
3 years ago
9

6

Chemistry
1 answer:
Vanyuwa [196]3 years ago
4 0

Answer:

If the volume of a gas increased from 2 to 6 L while the temperature was held constant, <u><em>the  pressure of the gas decreased by a factor of 3.</em></u>

Explanation:

Boyle's law that says "The volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure." This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

Pressure * Volume = constant

or

P * V = k

To obtain the proportionality factor k you must make the quotient:

k=\frac{V2}{V1} =\frac{6 L}{2 L}

k= 3

This means that <u><em>if the volume of a gas increased from 2 to 6 L while the temperature was held constant, the  pressure of the gas decreased by a factor of 3.</em></u>

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the Ray's go right through it

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An ethylene gas torch requires 300 L of gas at 0.8 atm. What will be the pressure of the gas if ethylene is supplied by a 200.0
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Answer:

1.2 atm

Explanation:

Given data

  • Volume of the gas in the tank (V₁): 200.0 L
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If we consider ethylene gas to be an ideal gas, we can find the pressure of ethylene gas in the tank using Boyle's law.

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How many grams of mg are in 534g of mgo<br> ​
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Please help: A 0.200 M NaOH solution was used to titrate a 18.25 mL HF
algol [13]

The molar concentration of the original HF  solution : 0.342 M

Further explanation

Given

31.2 ml of 0.200 M NaOH

18.2 ml of HF

Required

The molar concentration of HF

Solution

Titration formula

M₁V₁n₁=M₂V₂n₂

n=acid/base valence (amount of H⁺/OH⁻, for NaOH and HF n =1)

Titrant = NaOH(1)

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Input the value :

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