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REY [17]
3 years ago
10

What volume of DI water, in mL, must you use to dissolve 30.0 g of NaOH in order to make a 1.25 M solution? mL (round to whole n

umber)
Chemistry
1 answer:
jeka57 [31]3 years ago
4 0

Answer:

600mL

Explanation:

Molarity of a solution (M) = number of moles (n) ÷ volume (V)

number of moles = mass/molar mass

Molar mass of NaOH = 23 + 16 + 1

= 40g/mol

mole = 30/40

n of NaOH = 0.75mol

Using Molarity = n/V

V = number of moles ÷ molarity

V = 0.75 ÷ 1.25

V = 0.6L

In milliliters (mL), the volume of NaOH will be 0.6 × 1000

= 600mL

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Maksim231197 [3]

Answer: Molarity of the prepared solution is 1.75\times 10^{-3}mole/L

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute

V_s = volume of solution in ml = 500 ml

moles of solute =\frac{\text {given mass}}{\text {molar mass}}=\frac{0.258g}{294.19g/mol}=8.77\times 10^{-4}mol

Now put all the given values in the formula of molarity, we get

Molarity=\frac{8.77\times 10^{-4}moles\times 1000}{500ml}=1.75\times 10^{-3}mole/L

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Using the equation above, how many moles of Na are produced when 2.75 moles of H2 react with excess NaCl? will give BRAINLIEST
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Answer:

5.5 moles of sodium are produced

Explanation:

Given data:

Number of moles of hydrogen = 2.75 mol

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Solution:

Chemical equation:

H₂ + 2NaCl      →       2HCl + 2Na

Now we will compare the moles of hydrogen and sodium from balance chemical equation:

                    H₂         :       Na

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