Answer:
At this partial pressure of oxygen, Mb would be almost completely saturated but Hb would not.
Explanation:
The oxygen saturation curves for Mb and Hb are quite different. The curve for Mb is hyperbolic while that for Hb is sigmoidal.
Mb reaches oxygen saturation before Hb.
Thus, at a partial pressure of 40 mmHg, Mb is almost completely saturated but Hb is not.
"n" represents principal energy level or principal quantum number. Principal energy levels are then subdivided into sublevels. The level of principal energy level is always equal to number of sublevels. Therefore if <span>principal energy level</span> = 4, then there are also 4 sublevels present, namely: 4s, 4p, 4d and 4f sublevels.
Answer: The work done for the given process is -2188.7 J
Explanation:
To calculate the amount of work done for an isothermal process is given by the equation:

W = amount of work done = ?
P = pressure = 50.0 atm
= initial volume = 542 L
= final volume = 974 L
Putting values in above equation, we get:

To convert this into joules, we use the conversion factor:

So, 
The negative sign indicates the system is doing work.
Hence, the work done for the given process is -2188.7 J
Answer:
1597,5 gm AlCl3 decomposed
Explanation:
2AlCl3 --> 2Al + 3Al2 If you produce 15 moles of Al, how many grams of AlCl3 decomposed?
FIRST, you need to write down the the correct reaction. Your equation makes no sense
here is the correct question
2AlCl3 --> 2Al + 3Cl2 If you produce 15 moles of Al, how many grams of AlCl3 decomposed?
for every mole of Al produced, we decomposed a mole of AlCl3
so we produced 15 moles of Al, so we decomposed 15 moles of AlCl3
15 moles are 15 X 106.5 = 1597,5 gm AlCl3 decomposed
The ground-state electronic configuration follows the order of orbitals as shown in the first picture. So, we can deduce that the electronic configuration given is in order. However, each orbital must have a maximum number of electrons to be filled before it can move on to the next orbital. Since the d orbital must hold 10 electrons, that means that it should have held 5 electrons more. The missing 5 electrons were excited to the next 5p orbital.
<em>Thus, there are 5 excited electrons.</em>