Answer:
v=32.49 m/s
Explanation:
Given that
Distance ,d= 66 m
Initial speed of the car ,u = 0 m/s
Coefficient of friction ,μ = 0.8
Lets take the total mass of the car = m
The acceleration of the car is given as
a = μ g ( g= 10 m/s² )
Now by putting the values in the above equation we get
a= 0.8 x 10 m/s²
a= 8 m/s²
We know that ,final speed is given as
v²= u ²+ 2 a d
Now putting the value
v²=0² + 2 x 8 x 66
v²= 1056
v=32.49 m/s
Okay, so they want to basically Increase their grip, and they are taking advantage of the force of friction
Answer:
85 miles .
Explanation:
Displacement along the 110 South freeway = 260 - 150 = 110 miles
Displacement along the 110 North freeway = 150 - 175 = - 25 miles
Net displacement = 110 - 25 = 85 miles
So Joey's displacement from the 260 mile marker is 85 miles .
