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3 years ago

An object is thrown from the ground with an initial velocity of 30 m/s. What is the velocity at the point 25 m above the ground?

Physics

2 answers:

Dimas [21]3 years ago

8 0

Answer:

Explanation:

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dsp733 years ago

3 0

Answer:

It's a pretty simple suvat linear projectile motion question, using the following equation and plugging in your values it's a pretty trivial calculation.

V^2=U^2+2*a*x

V=0 (as it is at max height)

U=30ms^-1 (initial speed)

a=-g /-9.8ms^-2 (as it is moving against gravity)

x is the variable you want to calculate (height)

0=30^2+2*(-9.8)*x

x=-30^2/2*-9.8

x=45.92m

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A baseball is hit from a height of 4 feet above the ground with an initial velocity of 110 feet per second and at an angle of 35

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Answer:

Part a)

$h = 62.2 ft$

Part b)

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Explanation:

As we know that ball is hit with speed of 110 ft/s at an angle of 35 degree

so here we will say

$v_y = 110 sin35$

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now at the maximum height the vertical velocity will become zero

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here we have

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now we know that

$x = 375 ft$

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$y = 262.6 - 277.12 = -14.5 ft$

since its coming negative so it will not able to cross the pole

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