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lbvjy [14]
2 years ago
8

List the experiment procedures. Some steps have been filled in for you. You may need to adjust the numbers to match the steps yo

u decide on. 1. Identify the variables. 2. Write out your hypothesis in an if/then format. 3. Gather your materials. 4. 5. 6. 7. 8. 9. Analyze the data. 10. Analyze the data. Data Analysis Label a data table so that the experimenter can record observations for the sand and water temperatures at various points.
Chemistry
2 answers:
sergeinik [125]2 years ago
7 0

Answer:

I sadly don’t know what 7 & 8 is, but I hope this helps!

Explanation:

Quizlet.

Whitepunk [10]2 years ago
4 0

Answer:all u need to do is list what u are doing. Do u do FLVS? cuz tht was in ... have been filled in for you. You may need to adjust the numbers to match the steps you decide on. 1. Identify the variables. 2. Write out your hypothesis in an if/then format. 3.Gather your materials. 4. 5.

Explanation:

You might be interested in
The atomic mass of Cu is 63.5. Find its electrochemical equivalent​
FrozenT [24]

Answer:

The electrochemical equivalent of copper, Cu, is 3.29015544 × 10⁻⁷ g/C

Explanation:

The given parameters are;

The element for which the electrochemical equivalent is sought = Copper

The atomic mass of copper = 63.5

The electrochemical equivalent, 'Z', of an element or a substance is the mass, 'm', of the element or substance deposited by one coulomb of electricity, which is equivalent to a 1 ampere current flowing for a period of 1 second

Mathematically, we have;

m = Z·I·t = Z·Q

We have;

Cu²⁺ (aq) + 2·e⁻ → Cu

Therefore, one mole of Cu, is deposited by 2 moles of electrons

The charge carried one mole of electrons = 1 Faraday = 96500 C

∴ The charge carried two moles of electrons, Q = 2 × 96500 C = 193,000 C

Given that the mass of an atom of Cu = 63.5 a.m.u., the mass of one mole of Cu, m = 63.5 g

Z = \dfrac{m}{Q} = \dfrac{63.5 \ g}{193,000 \ C} = 3.29015544 \times 10^{-4} \, g \cdot C^{-1}

∴ Z = 3.29015544 × 10⁻⁴ g/C = 3.29015544 × 10⁻⁷ g/C

The electrochemical equivalent of copper, Cu, is Z = 3.29015544 × 10⁻⁷ g/C

7 0
3 years ago
When a scientific investigation runs for several years, which is most likely true?
Bingel [31]

Answer:

1. Many different hypotheses will be tested.

Explanation:

Scientists test every hypothesis they make for their investigation, before moving onto bigger conclusions.

4 0
3 years ago
Read 2 more answers
Isotopes that decay with a nuclear break-up and emit a significant amount of energy are said to be ________.
podryga [215]

Answer to this is Radioactive isotopes.

Isotopes are the species of the same element having different atomic masses that means the number of protons remains the same but number of neutrons do differ. For example _{1}^{2}\textrm{H} and _{1}^{3}\textrm{H} are the two isotopes of Hydrogen (_{1}^{1}\textrm{H} ).

Radioactive isotopes are the isotopes which release some kind of energy in the form of alpha particles, beta particles or gamma radiation. Examples of each of the decay processes are :

Alpha Decay: In this decay one alpha particle having atomic mass 4 and atomic number 2 or we can say a He molecule will come out. _{Z}^{A}\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_{2}^{4}\alpha

Beta Decay: In this decay a \beta particle is emitted increasing the atomic number of the reactant by 1 unit.

_{Z}^{A}\textrm{X}\rightarrow _{Z+1}^{A}\textrm{Y}+_{-1}^{0}\beta

Gamma Radiation: In this type of reaction only radiation is emitted out which does not change the original molecule.

_{Z}^{A}\textrm{X}\rightarrow _{Z}^{A}\textrm{X}+\gamma\text{ radiation}

3 0
2 years ago
the atoms of a certain element each contain 11 protons and 1 valence electron. what's the element and it's chemical reactivity?
Harrizon [31]
The element Sodium (Na) has 11 protons and 1 valence electron. 
8 0
3 years ago
Fe2O3+2Al=Al2O3+2Fe
True [87]
We determine the limiting reactant by using the moles present in the equation and the actual moles.
According to equation, ratio of Fe₂O₃ : Al = 1 : 2
Actual moles of Fe₂O₃ = 187.3 / (56 x 2 + 16 x 3)
= 1.17
Actual moles of Al = 94.51 / 27
= 3.5
Fe₂O₃ is limiting. Fe₂O₃ required:
(moles Al)/2 = 3.5/2 = 1.75
Moles to be added = 1.75 - 1.17
= 0.58
Mass to be added = moles x Mr
= 0.58 x (56 x 2 + 16 x 3)
= 92.8 grams
6 0
2 years ago
Read 2 more answers
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