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Diano4ka-milaya [45]
3 years ago
8

Is this correct? This is stoichiometry.

Chemistry
1 answer:
Viefleur [7K]3 years ago
7 0
Yes it’s is bc I said so
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What type of solid is this? This solid has high melting point, does not conduct electricity, and does not dissolve in water. Met
vivado [14]
The awnser It is iconic
5 0
3 years ago
When 6.040 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 18.95 grams of CO2 and 7.759 grams of H
algol [13]

Answer: The empirical formula is CH_2 and molecular formula is C_4H_8

Explanation:

We are given:

Mass of CO_2 = 18.95 g

Mass of H_2O= 7.759 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 18.59 g of carbon dioxide, =\frac{12}{44}\times 18.59=5.07g of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 7.759 g of water, =\frac{2}{18}\times 7.759=0.862g of hydrogen will be contained.

Mass of C = 5.07 g

Mass of H = 0.862 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{5.07g}{12g/mole}=0.422moles

Moles of H=\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.862g}{1g/mole}=0.862moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =\frac{0.422}{0.422}=1

For H =\frac{0.862}{0.422}=2

The ratio of C : H = 1: 2

Hence the empirical formula is CH_2.

The empirical weight of CH_2 = 1(12)+2(1)= 14 g.

The molecular weight = 56.1 g/mole

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{56.1}{14}=4

The molecular formula will be=4\times CH_2=C_4H_8

6 0
3 years ago
Calculate the force applied to a car with mass of 1200 kg that has an acceleration of 2 m/s/s.
bearhunter [10]

Answer:

2,400

Explanation:

F = m × a

F = 1200 × 2

F = 2,400

6 0
3 years ago
If a straight-chain hydrocarbon is a gas at room temperature, how many carbon atoms will it have?
Orlov [11]

The fewer the carbon atoms, the closer it is  to being a gas. The only one you have to check out is A which is hexane. You know that gasoline at the pumps has 8 carbons and its a liquid. So B and C are both not gases  because they are above 8.

C6 (hexane) is a liquid at room temperature not a gas.

The answer is D. If there is a gas present, it must be C3

6 0
3 years ago
Dihydrogen monoxide is a(n) ____. A. covalent compound B. molecular formula C. empirical formula D. Ionic compound​
olga_2 [115]

Answer:

D. Ionic compound

Explanation:

Just based on my opinion

Correct me if I'm wrong tnx:<

8 0
2 years ago
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