Is this correct? This is stoichiometry.

The mass-to charge ratio of the proton is found to be

andrezito [222]

Answer:

47 degrees

Explanation:

7 0

3 years ago

In addition to mass balance, oxidation-reduction reactions must be balanced such that the number of electrons lost in the oxidat

Fiesta28 [93]

Answer:

Part A: (1, 1, 4, 1, 1, 1)

Part B: (2, 6, 4, 2, 3, 8)

Explanation:

Redox reactions can be balanced using the half-reaction method. It has the following steps:

We write both half-reactions (reduction and oxidation)
We balance the masses using H⁺ and H₂O in acidic media or OH⁻ and H₂O in basic media.
We add electrons to balance electrically the half-reaction
We multiply the half-reaction by numbers to make sure the number of electrons gained and lost are the same.
We add both half-reactions and take the numbers to the general equation.

<em>Acidic solution</em>

SO₄²⁻(aq) + Sn²⁺(aq) + X ⇄ H₂SO₃(aq) + Sn⁴⁺(aq) + Y

1.

Reduction: SO₄²⁻ ⇒ SO₃²⁻

Oxidation: Sn²⁺ ⇒ Sn⁴⁺

2.

2 H⁺ + SO₄²⁻ ⇒ SO₃²⁻ + H₂O

Sn²⁺ ⇒ Sn⁴⁺

3.

2 H⁺ + SO₄²⁻ + 2 e⁻ ⇒ SO₃²⁻ + H₂O

Sn²⁺ ⇒ Sn⁴⁺ + 2 e⁻

4.

1 x [2 H⁺ + SO₄²⁻ + 2 e⁻ ⇒ SO₃²⁻ + H₂O]

1 x [Sn²⁺ ⇒ Sn⁴⁺ + 2 e⁻]

5.

2 H⁺ + SO₄²⁻ + 2 e⁻ + Sn²⁺ ⇄ SO₃²⁻ + H₂O + Sn⁴⁺ + 2 e⁻

2 H⁺ + SO₄²⁻ + Sn²⁺ ⇄ SO₃²⁻ + H₂O + Sn⁴⁺

Taking this to the general equation:

SO₄²⁻(aq) + Sn²⁺(aq) + 2 H⁺(aq) ⇄ H₂SO₃(aq) + Sn⁴⁺(aq) + H₂O(l)

Since H⁺ are spectator ions, they are not balanced automatically through this method and we have to balance them manually. In this case, we need to add 2 more H⁺ to the left.

SO₄²⁻(aq) + Sn²⁺(aq) + 4 H⁺(aq) ⇄ H₂SO₃(aq) + Sn⁴⁺(aq) + H₂O(l)

<em>Basic solution</em>

MnO₄⁻(aq) + F⁻(aq) + X ⇄ MnO₂(s) + F₂(aq) + Y

1.

Reduction: MnO₄⁻ ⇒ MnO₂

Oxidation: F⁻ ⇒ F₂

2.

2 H₂O + MnO₄⁻ ⇒ MnO₂ + 4 OH⁻

2 F⁻ ⇒ F₂

3.

2 H₂O + MnO₄⁻ + 3 e⁻ ⇒ MnO₂ + 4 OH⁻

2 F⁻ ⇒ F₂ + 2 e⁻

4.

2 × (2 H₂O + MnO₄⁻ + 3 e⁻ ⇒ MnO₂ + 4 OH⁻)

3 × (2 F⁻ ⇒ F₂ + 2 e⁻)

5.

4 H₂O + 2 MnO₄⁻ + 6 e⁻ + 6 F⁻ ⇄ 2 MnO₂ + 8 OH⁻ + 3 F₂ + 6 e⁻

4 H₂O + 2 MnO₄⁻ + 6 F⁻ ⇄ 2 MnO₂ + 8 OH⁻ + 3 F₂

Taking this to the general equation:

2 MnO₄⁻(aq) + 6 F⁻(aq) + 4 H₂O ⇄ 2 MnO₂(s) + 3 F₂(aq) + 8 OH⁻

This equation is balanced.

6 0

3 years ago

Arrange the following aqueous solutions, all at 25 ∘C, in order of decreasing acidity. 1 = most acidic; 4 = least acidic Rank fr

Akimi4 [234]

Answer:

1. 0.023 M H3O+.

2. pOH = 5.52.

3. pH=9.45

4. 0.0018 M OH-

Explanation:

Hello,

In this case, such order could be computed by means of the pH, the lower the pH the more acid the solution, thus:

1. 0.0018 M OH-:

$pOH=-log(0.018)=1.744\\pH=14-pOH=12.2$

2. 0.023 M H3O+

$pH=-log(0.023)=1.64$

3. pH=9.45

4.

$pH=14-5.52=8.48$

Therefore the order is

1. 0.023 M H3O+.

2. pOH = 5.52.

3. pH=9.45

4. 0.0018 M OH-

Best regards.

5 0

3 years ago

If 9.0 L of NO are reacted with excess O2 at STP, what is the volume in liters of the NO2 produced? Methane, the principal compo

d1i1m1o1n [39]

9 L of the NO2 was produced if 9.0 L of NO are reacted with excess $O_2$ at STP.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

According to the question, the given reaction is -

2NO(g) + O₂(g)--->2NO₂(g)

Since at STP one mole of a gas occupies the volume of 22.4 L.

As given in the question -

9 L of NO, i.e .

22.4 L = 1 mol

1 L = $\frac{1}{22.4 mol}$

For 9 L = $\frac{1 X 9L}{22.4 mol}$ = 0.40 mol

From the chemical reaction,

The Oxygen is in excess, hence NO becomes the limiting reagent, and will determine the moles of the product.

Hence, 2 moles of NO will produce 2 moles of NO₂.

Therefore, 0.40 mol of NO will produce 0.40 mol of NO₂.

Hence, the volume of NO₂ can be calculated as -

1 mol = 22.4 L

0.40 mol = 0.40 X 22.4 L = 9 L

Hence, 9 L of the NO₂ was produced.

Learn more about the ideal gas here:

brainly.com/question/27691721

#SPJ1

3 0

2 years ago

How is energy and gravity related to speed?

slavikrds [6]

Answer:

In classical theories of gravitation, the changes in a gravitational field propagate. A change in the distribution of energy and momentum of matter results in subsequent alteration, at a distance, of the gravitational field which it produces.

Explanation:

5 0

3 years ago

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