1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
GREYUIT [131]
3 years ago
6

Determine the differences In electronegativity ionic radius atomic radius and first ionization energy for oxygen and beryllium

Chemistry
1 answer:
Vilka [71]3 years ago
7 0

Answer:

Electronegativity  = 1.87.

Ionic radius = 109 pm.

Atomic radius = -39 pm

First ionization energy = 410 kJ/mol

Explanation:

Hello!

In this case, since electronegativity, ionic radius, atomic radius and first ionization energy are periodic properties that have specific trends, we can summarize it by realizing that oxygen and beryllium belong the same period 2 and differ in group, 6A and 2A respectively.

In such a way, the required comparison is written below:

Electronegativity = 3.44 (oxygen) - 1.57 (beryllium) = 1.87.

Ionic radius = 140 pm (oxygen)- 31 pm (beryllium) = 109.

Atomic radius = 73 pm (oxygen) - 112 pm (beryllium) = -39 pm

First ionization energy = 1310 kJ/mol (oxygen) - 900 kJ/mol (beryllium) = 410 kJ/mol

It means that electronegativity, ionic radius and first ionization energy increases from left to right whereas the atomic radius from right to left.

Best regards!

You might be interested in
Select the correct term to complete each sentence.
leva [86]

Answer: 1. halve

2. halve

3. double

Explanation:

The relationship between wavelength and energy of the wave follows the equation:

E=\frac{hc}{\lambda}

E= energy

\lambda = wavelength of the wave

h = Planck's constant  

c = speed of light

Thus as wavelength and energy have inverse realation, when wavelength will halve , energy will double.

2. The between wavenumber and energy of the wave follows the equation:

E=h\times c\times \bar{\nu}

E= energy

\bar{\nu}\nubar = wavenumber of the wave

h = Planck's constant  

c = speed of light

Thus as wavenumber and energy have direct relation, when wavenumber will halve , energy will be halved.

3. The relationship between energy and frequency of the wave follows the equation:

E=h\times \nu

where

E = energy

h = Planck's constant  

\nu = frequency of the wave

Thus as frequency and energy have direct realation, when frequency will double , energy will double.

3 0
3 years ago
A chemist heats the block of copper as shown in the interactive, then places the metal sample in a cup of oil at 25.00 °C instea
Mazyrski [523]

When the oil is added to the heated copper, the energy in the system is

conserved.

  • The mass of the oil in the cup, is approximately <u>64.73 grams</u>.

Reasons:

The question parameters are;

Temperature of the oil in the cup = 25.00°C

Final temperature of the oil and copper, T₂ = 27.33 °C

Specific heat of copper, c₂ = 0.387 J/(g·°C)

Specific heat capacity of oil, c₁ = 1.74 J/(g·°C)

Required:

The<em> mass of oil</em> in the cup.

Solution:

The mass of the copper, m₂ = 17.920 g

Temperature of copper after heating, T₂ = 65.17°C

Temperature of the copper after being placed in the cup of oil, T₂ = 27.33°C

Heat lost by copper = Heat gained by the oil

  • m₂·c₂·(T₂ - T₃) = m₁·c₁·(T₃ - T₁)

Therefore, we get;

17.920 × 0.387 × (65.17 - 27.33) = m₁ × 1.74 × (27.33 - 25)

262.4219136 = 4.0542·m₁

m₁ ≈ 64.73

  • The mass of the oil in the cup, m₁ ≈ <u>64.73 g</u>

Learn more here:

brainly.com/question/21406849

<em>Possible part of the question obtained from a similar question online, are;</em>

<em>The mass of the copper, m₂ = 17.920 g</em>

<em>Temperature of copper after heating = 65.17°C</em>

6 0
3 years ago
Aqueous magnesium chloride is added to aqueous silver nitrate. A white precipitate forms. Write the chemical equation for this r
Butoxors [25]

Answer:

1. Molecular equation

BaCl2(aq) + 2AgNO3(aq) –> 2AgCl(s) + Ba(NO3)2 (aq)

2. Complete Ionic equation

Ba²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO3¯ (aq) —> 2AgCl(s) + Ba²⁺(aq) + 2NO3¯(aq)

3. Net ionic equation

Cl¯(aq) + Ag⁺(aq) —> AgCl(s)

Explanation:

4 0
3 years ago
Read 2 more answers
I am a little confused
Sonbull [250]
The answer is D. I did that and i got it right.
7 0
3 years ago
Read 2 more answers
A sample contains 0.1895 g of salt per 50 g of seawater. What is its salinity?
Naily [24]
Use the rule of 3 simple
50 g mean 100% 0,1895 mean x% cross multiplie and calcule the x value x = 0,1895*100/50 = ?%
7 0
3 years ago
Other questions:
  • Why does your reflection in a mirror look different from your reflection in wood
    8·1 answer
  • Suppose we have a 12.2 L sample containing 0.50 mol oxygen gas at a pressure of 1 atm and a temperature of 25 degrees celcius. I
    10·1 answer
  • Molality (m) is _______. A. the number of moles of solute / the number of kilograms of solvent B. the number of kilograms of sol
    15·1 answer
  • What is the weight in grams of 3.36 × 1023 molecules of copper sulfate (CuSO4)?
    10·2 answers
  • When formic acid is heated, it decomposes to hydrogen and carbon dioxide in a first-order decay: HCOOH(g) →CO2(g) + H2 (g) The r
    10·1 answer
  • What is the total number of moles of sulfur atoms in 1 mole of Fe2(SO4)3
    10·2 answers
  • What is the silver ion concentration in a solution prepared by mixing 425 mL 0.397 M silver nitrate with 427 mL 0.459 M sodium p
    6·1 answer
  • What is the molarity of a solution made with 400 grams of copper II chloride in 3.5 liters of water?
    6·1 answer
  • Which of the following are considered physical changes?
    13·1 answer
  • Values of R, the ideal gas constant, and the ideal gas equation are given below. Use these to solve the problems.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!