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adell [148]
3 years ago
5

4.07 x 10-17 (5.6 x 10") (5.8 x 105)

Chemistry
1 answer:
Andrej [43]3 years ago
3 0
4.07 x 10-17 = 23.7
(5.6 x 10”) (5.8 x 105)= log(100)
log(7)
Hope this helped
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5 0
4 years ago
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Compounds X and Y are both C6H13Cl compounds formed in the radical chlorination of 3-methylpentane. Both X and Y undergo base-pr
zubka84 [21]

Answer:

Y is a 3-chloro-3-methylpentane.

The structure is shown in the figure attached.

Explanation:

The radical chlorination of 3-methylpentane can lead to a tertiary substituted carbon (Y) and to a secondary one (X).

The E2 elimination mechanism, as shown in the figure, will happen with a simulyaneous attack from the base and elimination of the chlorine. This means that primary and secondary substracts undergo the E2 mechanism faster than tertiary substracts.

6 0
3 years ago
Exactly 15.0 g of a substance can be dissolved in 150.0 g of water what is the solubility of the substance in grams per 100 g of
Leokris [45]
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3 years ago
How many moles of Cs are contained in 3 moles of Cs3PO4?
Alenkinab [10]

Answer:

\boxed {\boxed {\sf 9 \ moles \ Cs}}

Explanation:

We are given the compound: Cs₃PO₄

According to the formula, 1 mole of cesium phosphate contains 3 moles of cesium, 1 mole of phosphate, and 4 moles of oxygen.

Therefore, there are 3 moles of cesium for 1 mole of cesium phosphate.

\frac {3 \ mol \ Cs}{1 \ mol \ Cs_3PO_4}

We want to calculate the moles of cesium in 3 moles of cesium phosphate, so we multiply the ratio by 3.

3 \ mol \ Cs_3PO_4 *\frac {3 \ mol \ Cs}{1 \ mol \ Cs_3PO_4}

3 *\frac {3 \ mol \ Cs}{1 }= 9 \ mol \ Cs

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