Answer:
Rate constant = 0.0237 M-1 s-1, Order = Second order
Explanation:
In this problem, it can be observed that as the concentration decreases, the half life increases. This means the concentration of the reactant is inversely proportional to the half life.
The order of reaction that exhibit this relationship is the second order of reaction.
In the second order of reaction, the relationship between rate constant and half life is given as;
t1/2 = 1 / k[A]o
Where;
k = rate constant
[A]o = Initial concentration
k = 1 / t1/2 [A]
Uisng the following values;
k = ?
t1/2 = 113
[A]o = 0.372M
k = 1 / (113)(0.372)
k = 1 / 42.036 = 0.0237 M-1 s-1
In the first shell there is 2 electrons and on the second shell there is 4 elections.
Answer: 1.05
Explanation:
On ionization, hydrobromic acid completely dissociates into hydrogen ion and bromine ion. The equation is stated below
HBr <--> H+ + Br-
Recall that pH = - log(H+)
Concentration of hydrogen ion (H+) = 0.09M
So, pH = - log (0.09)
pH = - (-1.05)
pH = 1.05
The pH of 0.09M solution of HBr is 1.05. Thus, it is highly acidic.
Explanation:
An Element is one and a compound is more than 2elements
I'm not 100% sure that this is right but I think D. is correct.
