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schepotkina [342]
3 years ago
5

HELP FAST!!!!

Chemistry
1 answer:
Viktor [21]3 years ago
4 0
Try d)kinetic energy, if wrong sorry
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The specific heat of nickel is 0.44 J/g*⁰C. How much energy needed to change the temperature of 95.4g of nickel from 22⁰C to 32⁰
valentinak56 [21]
To determine the heat or energy needed for the process, we use the equation,
                                               H  = mcpdT
where m is the mass, cp is the specific heat and dT is the temperature difference. 
                                               H = (95.4g)(0.44 J/g°C)(32°C - 22°C)
                                                   = 419.76 J
Thus, the amount of heat that should be ABSORBED is approximately 419.76 J. 
8 0
3 years ago
Read 2 more answers
Metals are extracted from their ores.
zvonat [6]
1.  Copper is very useful, so people want as much as possible.
2.  We are running out, so we are extracting all the copper that we can to keep up with our needs.
7 0
3 years ago
A student performs an experiment to determine the density of a sugar solution. She obtains the following results: 1.79 g/mL, 1.8
Pachacha [2.7K]

Answer:

(B) Her results are both precise and accurate.

Explanation:

In Chemistry, Accuracy refers to how close a measurement is to it's standard value or known value. On the other hand, Precision means how close two measurement are to each other regardless whether the results are accurate or not.

In the above question, all the above results are very close to each other. That's why the results are Precise to each other. All the results  are close enough to the actual value of the experiment. That's why the result are also accurate.

5 0
4 years ago
You wish to make 250. mL of 0.20 M KCl from a stock solution of 1.5 M KCl and DI water.
Nitella [24]

The question requires us to use the dilution formula M_iV_i=M_fV_f, where M_i and V_i are the stock concentration and volume respectively, then M_f and V_f are the dilute concentration and volume respectively.

a. C_s_t_o_c_k= 1.5 M KCI, C_d_i_l_u_t_e=0.20M KCl, V_d_i_l_u_t_e=250ml KCl

b.M_iV_i=M_fV_f\\\implies V_i= \frac{M_fV_f}{M_i} = \frac{0.20M \times 250ml}{1.5M} = 33.3\ ml

To prepare the solution 33.3ml of 1.5M KCl is diluted to a total final volume of 250ml.


8 0
4 years ago
Which type of energy is released in chemical reactions?
Elena-2011 [213]
Chemical energy is released 
3 0
3 years ago
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