Answer:
The MOLARITY of a solution tells how many moles of solute are present per liter
Explanation:
Molarity is a sort of concentration.
It is written as M (mol/L)
The kinetic energy and the physical state of water depend strongly on the temperature;
- Firstly, The kinetic energy of water on a hot stove is higher than that on the counter in the freezer; that the kinetic energy is directly proportional to the temperature according to the relation:
; where R is the universal gas constant, T is the temperature and NA is Avogadro number.
As the temperature increases, the speed of colliding molecules increases and the kinetic energy increases.
- Secondly, The physical state of water depends on the temperature; water has three states (gas, liquid and solid) depends on the temperature.
- If a glass of water is putt on the counter in the freezer, it will be converted to the solid state (ice).
- And, as if it is putt on a hot stove, it will be vapor (gaseous state).
Explanation:
2,4-DNP is negative: aldehyde and ketone absent
Chromic acid is negative: alcohol absent.
KMnO4 test negative: alkene absent
The only positive result is for Fe(OH)2.
Nitro group-containing compounds react with ferrous hydroxide to give amine and ferric hydroxide red ppt. Hence given compound contains the nitro group (-NO2).
Explanation:
It is given that,
Initial orbit of electrons, ![n_i=4](https://tex.z-dn.net/?f=n_i%3D4)
Final orbit of electrons, ![n_f=2](https://tex.z-dn.net/?f=n_f%3D2)
We need to find energy, wavelength and frequency of the wave.
When atom make transition from one orbit to another, the energy of wave is given by :
![E=-13.6(\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2})](https://tex.z-dn.net/?f=E%3D-13.6%28%5Cdfrac%7B1%7D%7Bn_f%5E2%7D-%5Cdfrac%7B1%7D%7Bn_i%5E2%7D%29)
Putting all the values we get :
![E=-13.6(\dfrac{1}{(4)^2}-\dfrac{1}{(2)^2})\\\\E=2.55\ eV](https://tex.z-dn.net/?f=E%3D-13.6%28%5Cdfrac%7B1%7D%7B%284%29%5E2%7D-%5Cdfrac%7B1%7D%7B%282%29%5E2%7D%29%5C%5C%5C%5CE%3D2.55%5C%20eV)
We know that : ![1\ eV=1.6\times 10^{-19}\ J](https://tex.z-dn.net/?f=1%5C%20eV%3D1.6%5Ctimes%2010%5E%7B-19%7D%5C%20J)
So,
![E=2.55\times 1.6\times 10^{-19}\\\\E=4.08\times 10^{-19}\ J](https://tex.z-dn.net/?f=E%3D2.55%5Ctimes%201.6%5Ctimes%2010%5E%7B-19%7D%5C%5C%5C%5CE%3D4.08%5Ctimes%2010%5E%7B-19%7D%5C%20J)
Energy of wave in terms of frequency is given by :
![E=hf](https://tex.z-dn.net/?f=E%3Dhf)
![f=\dfrac{E}{h}\\\\f=\dfrac{4.08\times 10^{-19}}{6.63\times 10^{-34}}\\\\f=6.14\times 10^{14}\ Hz](https://tex.z-dn.net/?f=f%3D%5Cdfrac%7BE%7D%7Bh%7D%5C%5C%5C%5Cf%3D%5Cdfrac%7B4.08%5Ctimes%2010%5E%7B-19%7D%7D%7B6.63%5Ctimes%2010%5E%7B-34%7D%7D%5C%5C%5C%5Cf%3D6.14%5Ctimes%2010%5E%7B14%7D%5C%20Hz)
Also, ![c=f\lambda](https://tex.z-dn.net/?f=c%3Df%5Clambda)
is wavelength
So,
![\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{6.14\times 10^{14}}\\\\\lambda=4.88\times 10^{-7}\ m\\\\\lambda=488\ nm](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7Bc%7D%7Bf%7D%5C%5C%5C%5C%5Clambda%3D%5Cdfrac%7B3%5Ctimes%2010%5E8%7D%7B6.14%5Ctimes%2010%5E%7B14%7D%7D%5C%5C%5C%5C%5Clambda%3D4.88%5Ctimes%2010%5E%7B-7%7D%5C%20m%5C%5C%5C%5C%5Clambda%3D488%5C%20nm)
Hence, this is the required solution.