Answer:
Doggy
Explanation: Its more exotic :)
One aluminum atom will cost 0.84 × 10⁻²³ cents.
Explanation:
Aluminium costs 85 cents per 453.592 grams.
number of moles = mass / atomic weight
number of moles of aluminium = 453.592 / 27 = 16.8 moles
To calculate the number of aluminum atoms we use the Avogadro's number:
if 1 mole of aluminum contains 6.022 × 10²³ aluminum atoms
then 16.8 moles of aluminum contains X aluminum atoms
X = (16.8 × 6.022 × 10²³) / 1 = 101.17 × 10²³ aluminum atoms
Now, taking in account the aluminium price, we devise the following reasoning:
if 101.17 × 10²³ aluminum atoms costs 85 cents
then 1 aluminum atom costs Y cents
Y = (1 × 85) / (101.17 × 10²³) = 0.84 × 10⁻²³ cents
Learn more about:
Avogadro's number
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Answer:
17.1 L
Explanation:
P1V1/T1 = P2V2/T2 T is in K
P1V1/T1 * T2/P2 = V2
735 * 7.31 / (45+273.15) * (55+ 273.15)/325 = V2
V2 = 17.1 L
The moles of B that will be needed to convert 2 moles of A into as many moles of C as possible is 6 moles
Explanation
3A +9B → 5C
The moles of B are calculated using the mole ratio.
That is; from the equation above the mole ratio of A:B is 3:9
If the moles of A required is 2 moles therefore the moles of B
= 2 x9/3= 6 moles
