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Lelu [443]
3 years ago
6

How do you find the metal “M”

Chemistry
1 answer:
Elodia [21]3 years ago
5 0

M = Sr (strontium)

<em>Step 1.</em> Calculate the <em>moles of CO_2</em>.

Moles of CO_2 = 0.395 g CO_2 × (1 mol CO_2/44.01 g CO_2)

= 0.008 975 mol CO_2

<em>Step 2</em>. Calculate the <em>moles of MCO_3</em>.

Moles of MCO_3 = 0.008 975 mol CO_2 × (1 mol MCO_3/1 mol CO_2)

= 0.008 975 mol MCO_3

<em>Step 3</em>. Calculate the molar mass of <em>MCO_3</em>

MM = grams/moles = 1.324 g/0.008 75 mol = 147.5 g/mol

<em>Step 4</em>. Calculate the <em>atomic mass of M</em>

M_r = <em>x</em> + 12.01 + 3×16.00 = <em>x</em> + 60.01 = 147.5

<em>x</em> = 147.5 – 60.01 = 87.5

<em>Step 5. Identify M</em>.

The element with the closest atomic mass is Sr (A_r = 87.6).

∴ M = Sr and the compound is SrCO_3.

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4 0
3 years ago
The equilibrium concentrations of the reactants and products are [HA]=0.280 M, [H+]=4.00×10−4 M, and [A−]=4.00×10−4 M. Calculate
Tems11 [23]

Answer:

6.24

Explanation:

The following data were obtained from the question:

Concentration of HA, [HA] = 0.280 M,

Concentration of H+, [H+] = 4×10¯⁴ M

Concentration of A-, [A−] = 4×10¯⁴ M

pKa =.?

Next, we shall write the balanced equation for the reaction. This is given below:

HA <===> H+ + A-

Next, we shall determine the equilibrium constant Ka for the reaction. This can be obtained as follow:

Equilibrium constant for a reaction is simply the ratio of concentration of the product raised to their coefficient to the concentration of the reactant raised to their coefficient.

The equilibrium constant for the above equation is given below:

Ka = [H+] [A−] /[HA]

Concentration of HA, [HA] = 0.280 M,

Concentration of H+, [H+] = 4×10¯⁴ M

Concentration of A-, [A−] = 4×10¯⁴ M

Equilibrium constant (Ka) =

Ka = (4×10¯⁴ × 4×10¯⁴) / 0.280

Ka = 1.6×10¯⁷/ 0.280

Ka = 5.71×10¯⁷

Therefore, the equilibrium constant for the reaction is 5.71×10¯⁷

Finally, we shall determine the pka for the reaction as follow:

Equilibrium constant, Ka = 5.71×10¯⁷

pKa =?

pKa = – Log Ka

pKa = – Log 5.71×10¯⁷

pKa = 6.24

Therefore, the pka for the reaction is 6.24.

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Roman55 [17]

The answer of this answer is given in the attached file

Download pdf
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Which of the four cars had the least net force applied to it when it was launched down the ramp
castortr0y [4]

The least net force applied : Car 3(12 N)

<h3>Further explanation  </h3>

Newton's 2nd law explains that the acceleration produced by the resultant force on an object is proportional and in line with the resultant force and inversely proportional to the mass of the object  

∑F = m. a  

Car 1 ⇒m=0.5 kg, a=36 m/s²

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