Write orbital diagrams (boxes with arrows in them) to represent the electron configurations of carbon before and after sp hybrid
ization.
1 answer:
You might be interested in
Answer: Option (3) is the correct answer.
Explanation:
When there is a negative charge on an atom then we add the charge with the number of electrons. Whereas when there is a positive charge on an atom then we subtract the charge from the number of electrons.
Atomic number of chlorine is 17. So, number of electrons present in is 17 + 1 = 18 electrons.
Atomic number of cobalt is 27. So, number of electrons present in is 27 - 4 = 23 electrons.
Atomic number of iron is 26. So, number of electrons present in is 26 - 2 = 24 electrons.
Atomic number of vanadium is 23. So, number of electrons present in V is 23 electrons.
Atomic number of scandium is 21. So, number of electrons present in is 21 + 2 = 23 electrons.
Thus, we can conclude that out of the given species, has the greatest number of electrons.