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Triss [41]
3 years ago
7

Write orbital diagrams (boxes with arrows in them) to represent the electron configurations of carbon before and after sp hybrid

ization.

Chemistry
1 answer:
NemiM [27]3 years ago
4 0
Carbon has an electron configuration of 1s^2 2s^2 2p^2. During sp hybridization, one s and one p orbital of carbon combine to form two sp hybrid orbitals.


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A chemist found that 4.69 g of sulfur combined with fluorine to produce 15.81 g of a gas. what is the empirical formula of the g
timofeeve [1]
Mass of sulfur combined - 4.69 g
Mass of gas produced is 15.81 g, therefore mass of fluorine is (15.81-4.69) = 11.12 g
Number of sulfur moles - 4.69 g/32 g/mol = 0.15 mol
Number of fluorine moles - 11.12 g/ 19 g/mol = 0.585 mol
divide both by least number of moles 
S - 0.15/0.15 = 1
F - 0.585/0.15 = 3.9 rounded off is 4
ratio of S to F = 1:4Therefore formula of the gas is SF₄
7 0
3 years ago
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Do CO2 and h2o have the same geometry
Svetach [21]
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7 0
3 years ago
A reaction has ∆H = −356 kJ and ∆S = −36 J/K. Calculate ∆G (kJ) at 25°C.
Cloud [144]

Answer: -345.2 KJ

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T=25+273=298 K

dG= -356 x1000-298(-36)= -356000+10728

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5 0
2 years ago
Which statement correctly describes the relationship between reactant and yield? The actual yield is calculated from the amount
melamori03 [73]
The statement which correctly describe the relationship between the reactants and the yield is this: 'the theoretical yield is calculated from the amount of the limiting reactants present'. The theoretical yields is the ideal maximum amount of a product that can be produced during a chemical reaction while the limiting reactant is the reactant that determines the maximum amount of product that can be formed.
8 0
3 years ago
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A student attempted to identify an unknown compound by the method used in the experiment. She found that when she heated the sam
yanalaym [24]
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<span>
1 mole of Na2CO3 = 106 g </span>
<span>2 moles of NaCl     = 2 x 58.4
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</span>Na2CO3 would increase by 116.8 / 106 = 1.10 to form 2NaCl.
<span>0.4862 g x 1.10 = 0.515 grams of NaCl.
</span>
K2CO3 + 2Cl- ⇒ 2KCl + CO3^-2 
<span>1 mole of K2CO3 = 138.2 g </span>
<span>2 moles of KCl = 149.1 </span>
<span>
K2CO3 would increase by </span>149.1 /138.2 = 1.079 <span>to form 2KCl
</span>
<span> 0.4862 x 1.079 = 0.5246 g</span>


3 0
3 years ago
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