Answer:
Partial pressure of
in the gas was 733 torr and mass of
in the sample was 2.12 g.
Explanation:
a) Total pressure of gas = (partial pressure of water vapour)+(partial pressure of
)
Here partial pressure of water vapour is 21 torr and total pressure of gas is 754 torr.
So, partial pressure of
= (total pressure of gas)-(partial pressure of water vapour) = (754 torr) - (21 torr) = 733 torr
b) Lets assume that
behaves ideally. Hence-
PV=nRT
where P is pressure of
, V is volume of
, n is number of moles of
, R is gas constant and T is temperature in kelvin
here P = 733 torr =
= 0.9646 atm
V = 0.65 L, R = 0.082 L.atm/(mol.K), T=(273+22)K = 295 K
So, 
= 
= 0.0259 moles
As 3 moles of
are produced from 2 moles of
therefore 0.0259 moles of
are produced from
moles or 0.0173 moles of
.
Molar mass of
= 122.55 g
So mass of
in sample = 
= 2.12 g
It is a radio wave
Explanation:
The energy of an electromagnetic waves is related to its frequency by the equation:

where
h is the Planck constant
f is the frequency of the wave
We notice that the energy of an electromagnetic wave is proportional to its frequency. This means that waves with higher frequencies, such as gamma rays, x-rays, are more energetic, while waves with lower frequencies, such as microwave and radio waves, are the less energetic.
In this case, we want to find the frequency of a wave with energy
E = 0.000001 eV
Converting into Joules,

Solving for the frequency,

Which falls in the range of frequency of radio waves.
Learn more about electromagnetic waves:
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Answer:A
Explanation:Binary Fission, meaning ‘getting divided into half’ is a type of asexual reproduction where a single living cell grows twice its size and then splits to form two identical daughter cells, each carrying a copy of the parent cell’s genetic material. Examples of cells that use binary fission for division
Answer:
Both student have same percent error.
Explanation:
Given data:
Actual mass of object = 0.54 g
Measured value by one student = 0.59 g
Measured value by second student = 0.49 g
Percent error = ?
Solution:
Formula
Percent error = (measured value - actual value / actual value) × 100
Percent error of first student:
percent error = (0.59 g - 0.54 / 0.54 ) ×100
percent error = 9.3 %
Percent error of second student:
Percent error = (0.49 g - 0.54 / 0.54 ) ×100
Percent error = - 9.3 %
Both student have same percent error. The only difference is that first student measure the greater value then actual value and second student measure the less value then actual, however difference was same and gives same percent error.